A block slides on a table pulled by a string attached to a hanging weight. In case 1 the block slides without friction and in ca
2 answers:
Response:
In the second scenario
Clarification:
Reasoning:
Friction opposes motion.
In scenario one, the block glides without any friction present, indicating a smooth surface allowing minimal net force to pull the string.
In the second scenario, kinetic friction plays a role between the sliding block and the table, where kinetic friction is expressed as:
with relevant variables being as the coefficient of friction and N as the normal force.
This means the necessary net force becomes:
Thus, the force is greater in the second situation.
Consequently, the tension is also heightened in the second scenario.
You might be interested in
Answer:
Explanation:
a) La fuerza neta que actúa sobre la caja en la dirección vertical es:
Fnet=Fg−f−Fp *sin45 °
aquí Fg representa la fuerza gravitacional, f es la fuerza de fricción, y Fp es la fuerza de empuje.
Fnet=ma
ma=Fg−f−Fp *sin45 °
a=
=0.24 m/s²
Vf =Vi +at
=0.48+0.24*2
Vf=2.98 m/s
b)
Fnet=Fg−f−Fp *sin45 °
=Fg−0.516Fp−Fp *sin45 °
=30-1.273Fp
Fnet=0 (Ya que la velocidad es constante)
Fp=30/1.273
=23.56 N