Answer:
the temperature on the left side is 1.48 times greater than that on the right
Explanation:
GIVEN DATA:

T1 = 525 K
T2 = 275 K
It is known that


n and v are constant on both sides. Therefore we have

..............1
let the final pressure be P and the temperature 

..................2
similarly
.............3
divide equation (2) by equation (3)
![\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B11%7D%5E%7B-2%2F3%7D%20%5Cfrac%7B21%7D%7B11%7D%5E%7B5%2F3%7D%20%3D%20%5B%5Cfrac%7BT_1%20%7Bf%7D%7D%7BT_2%20%7Bf%7D%7D%5D%5E%7B5%2F3%7D)

thus, the left side temperature equals 1.48 times the right side temperature
Solution:
/ Em₀ = 0.30
Explanation:
In this problem, we apply the connection between mechanical energy, kinetic energy, and gravitational potential energy.
K = ½ m v²
U = mgh
We assess the mechanical energy at two positions:
Initial. Lower
Em₀ = K = ½ m v²
At its highest point
= U = mg and
Now let's compute
Em₀ = ½ m 3.6²
Em₀ = m 6.48
= m 9.8 × 0.2
= m 1.96
Thus the energy lost is given by:
/ Em₀ = m 1.96 / m 6.48
/ Em₀ = 0.30
This means that 30% of the sun's energy is transformed into potential energy.
There are various conversion possibilities.
This energy changes into thermal energy affecting the spores and air, since it cannot be regained.