"The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N obj

Answer:

Lines a and b are considered parallel due to their corresponding angles being equal.

Step-by-step explanation:

The corresponding angle postulate states that two lines are parallel when a transversal intersects them and their corresponding angles are congruent.

In this case, line a and line b are intersected by transversal e, with both corresponding angles measuring 110 (which are congruent), hence, according to the corresponding angle postulate, we can conclude that line a and line b are indeed parallel to each other.

Answer:

The solution to this problem indicates that Hernry invested $18,000 in stocks and $6,000 in bonds.

Step-by-step explanation:

First, you need to multiply 6 by 3. The outcome is 18, meaning it is three times higher than the bond amount. Next, subtract $24,000 from $18,000, which gives you $6,000, representing the bond investment. Hence, it is three times less than the stocks as the question describes.

Answer:

together they rake leaves in one minute.

Step-by-step explanation:

If Maya takes x minutes to rake, then in one minute, she rakes leaves.

For Carla, if her raking takes y minutes, in one minute she rakes leaves.

Thus, to find the amount they work together in one minute, we add both of their contributions for that minute, resulting in:

Finally, simplifying this expression gives:

As a result, they collectively rake leaves in a minute.

Response:

Step-by-step explanation:

Assuming there are 100 sour candies, thus-  

since 26% of the candies are grape, it follows that 26% of 100 candies means we have 26 grape candies

Consequently, the remaining candies that are not grape amount to 100-26 = 74

Applying the multiplication principle:

P(A ∩ B) = P(A)/ P(B|A)  

 Initially, there are 26 grape candies, therefore the probability of selecting the first grape candy =  26C1 = 26

 After choosing the first one, we put the selected grape candy back, so there are still 100 candies total P(B|A) = 100C3 = 100 x 99 x 98 x 97!/3! X 97!

= 50 x 33 x 98

Thus, the probability becomes 1/ 50 x 33 x 98 x 26