Magnesium and nitrogen react in a combination reaction to produce magnesium nitride: 3 Mg N2 → Mg3N2 In a particular experiment,

The percentage of KCl present in the mixture is approximately <span>40%</span><span>If we consider a 100-gram sample of the mixture:ω(K) = 44.20% ÷ 100% = 0.442.
m(K) = 0.442 · 100 g = 44.2 g.</span>n(K) = 44.2 g ÷ 39.1 g/mol.
n(K) = 1.13 mol.
n(KCl) + n(KNO₃) = n(K)
m(KCl) = x.
m(KNO₃) = y.
Two equations:
1) x + y = 100 g.
2) m(KCl)/M(KCl) + m(KNO₃)/M(KNO₃) = 1.13 mol.
x/74.55 g/mol + y/101.1 g/mol = 1.13 mol.
From the first equation, we find x = 100 - y and substitute into the second equation:
(100 - y)/74.55 + y/101.1 = 1.13 /×101.1.
135.61 - 1.356y + y = 114.24.
0.356y = 22.37 g.
y = 62.83 g.
Thus, x = m(KCl) = 100 g - 62.83 g = 37.17 g.

Answer: The change in enthalpy for each mole of zinc involved in the reaction is 152.4 kJ/mol.

Explanation:

First, we need to determine the moles of Zn and HCl.

The molar mass of Zn is 65 g/mole

and,

Next, we must identify the limiting reagent and the excess reagent.

The chemical reaction given is:

According to the balanced reaction we find that

1 mole of reacts with 2 moles of

Thus, 0.0206 moles of react with moles of

This leads us to determine that is the excess reagent because the moles provided exceed the required moles, while is limiting and restricts product formation.

Now to find the enthalpy change for each mole of zinc reacting in this reaction.

From the reaction we gather that,[ [TAG_59]]

0.0206 moles of Zn yield heat = 3.14 kJ

This implies that 1 mole of Zn generates heat =

Hence, the enthalpy change per mole of zinc involved in this reaction amounts to 152.4 kJ/mol.

Answer:

C

Explanation

My teacher mentioned that, for instance, Florida tends to be warm, while Central America can have both hot and cold temperatures, and a jacket isn't necessary. I don't recall many details.

<span>Using PV=nRT, which represents a universal constant for any state, we have: P1V1/n1T1=R and P2V2/n2T2=R; This implies that: P1V1/n1T1=P2V2/n2T2 Thus we can express it as V1/n1=V2/n2. Rearranging yields: V2=V1 x (n2/n1) = 750 mL x ((0.65+0.35)/(0.65)) = 1200 mL = 1.2 L... with 2 significant figures</span>

Response: Water molecules migrate from the dilute to the concentrated solution

Clarification:

During osmosis, when a solution is separated by a semipermeable membrane, the solvent (commonly water) moves from the less concentrated solution, regarding solute content, through the semipermeable membrane towards the solution with a higher concentration to balance the concentration levels between the two solutions.

Thus, in this scenario, water molecules flow from the 0.4M sugar solution to the 0.7M sugar solution through the semipermeable membrane.