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Rashid
1 month ago
7

A tiny pencil mark just visible to the naked eye contains about 3 × 1017 atoms of carbon. what is the mass of this pencil mark i

n grams?
Chemistry
1 answer:
Alekssandra [3K]1 month ago
6 0
The quantity of carbon atoms in the pencil mark amounts to 3 x 10^17. Given that the atomic weight of carbon is 12.01 amu, it follows that 12.01 g of carbon contains 6.022 x 10^23 atoms. Thus, we can set up the equation: 12.01 g carbon/ 6.022 x 10^23 atoms (3 x 10^17 atoms) (12.01 g carbon/ 6.022 x 10^23 atoms). By canceling out the atoms, we have (3 x 10^17) (12.01 g carbon/6.022 x 10^23) and then completing the division and multiplication yields 6 x 10^-6 g of carbon. Therefore, the mass of the pencil mark is 6 x 10^-6 g.
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Response:

Here's my calculation

Clarification:

Assume the starting concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

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1. We will need a chemical equation with concentrations, so let's compile all the information in one location.

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3. Plot the initial values

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the image above shows a chamber with a fixed volume filled with gas at a pressure of 1560 mmHg and a temperature of 445.0 K. If
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Answer:

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<psubstituting:>

\frac{1560 mmHg}{445 K} =\frac{P2}{312 K}

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P2=\frac{1560 mmHg}{445 K} *312K

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</psubstituting:>
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