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vredina
27 days ago
6

A 0.652-g sample of a pure strontium halide reacts with excess sulfuric acid. the solid strontium sulfate formed is separated, d

ried, and found to weigh 0.755 g. what is the formula of the original halide?
Chemistry
1 answer:
lorasvet [2.5K]27 days ago
4 0

Answer:

The original halide's formula is SrCl₂.

Explanation:

  • The chemistry reaction's balanced equation is:

SrX₂ + H₂SO₄ → SrSO₄ + 2 HX, where X indicates the halide.

  • Based on the equation's stoichiometry, 1.0 mole of strontium halide yields 1.0 mole of SrSO₄.
  • The moles of SrSO₄ (n = mass/molar mass) = (0.755 g) / (183.68 g/mole) = 4.11 x 10⁻³ mole.
  • The moles of SrX can thus be calculated as 4.11 x 10⁻³ moles based on stoichiometry from the balanced equation.
  • n = mass / molar mass, thus n =  4.11 x 10⁻³ moles and mass = 0.652 g.
  • The molar mass of SrX₂ is calculated using mass / n = (0.652) / (4.11 x 10⁻³ moles) = 158.62 g/mole.
  • The molar mass of SrX₂ (158.62 g/mole) = Atomic mass of Sr (87.62 g/mole) + (2 x Atomic mass of halide X).
  • Calculating the atomic mass of halide X, we find = (158.62 g/mole) - (87.62 g/mole) / 2 = 71 / 2  g/mole = 35.5 g/mole.
  • This identifies the atomic mass of Cl.
  • Consequently, the original halide's formula is SrCl₂.
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11 days ago
What is the specific heat of an unknown metal if 1.67 kcal of energy are required to raise the temperature of 79.2 g sample of t
VMariaS [2690]

Answer:

The solution to your inquiry is C = 0.000333 kcal/g°C

or C = 0.333 cal/g°C

Explanation:

Data

Q = 1.67 kcal

mass = 79.2 g

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Formula

Q = mCΔT

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Simplifying

C = 1.67 / 5013.4

Final Result

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4 0
1 month ago
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Answer:

A total of 2667 tires are required to satisfy the annual power needs of ten homes.

Explanation:

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E_{out} = \eta \cdot E_{in}

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28 days ago
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The formula for Molarity is given by:

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