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Hatshy
16 days ago
10

Which letter correctly identifies the part of the hydrologic cycle that is most directly affected by impervious building materia

ls, such as concrete and asphalt?
Physics
1 answer:
serg [2.5K]16 days ago
3 0

Infiltration

Explanation:

The feature of the hydrologic cycle most impacted by impervious surfaces like concrete and asphalt is infiltration.

  • Infiltration is crucial within the hydrologic cycle.
  • Concrete and similar materials hinder water absorption into the ground.
  • This adversely affects existing groundwater systems.
  • A rise in surface runoff can occur, leading to potential flooding.
  • Infiltration plays a pivotal role in the water cycle.
  • It supplies water to plant roots and replenishes groundwater reserves.
  • Impervious surfaces disrupt this natural process.

learn more:

Biogeochemical cycle

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Softa [2035]

Answer:

I do not communicate in Spanish

Explanation:

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3 days ago
A bus slows down uniformly from 75.0 km/h to 0 km/h in 21 s. How far does it travel before stopping?
Yuliya22 [2446]

1 hour = 3,600 seconds
1 km = 1,000 meters

75 km/hour = (75,000/3,600) m/s = 20-5/6 m/s

The mean speed during the deceleration is

                                   (1/2)(20-5/6 + 0) = 10-5/12 m/s.

Traveling at this average speed for 21 seconds,
the bus covers

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7 0
1 month ago
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A person on a diet loses 1.6 kg in a week. How many micrograms/second (µg/s) are lost?
Sav [2230]
To calculate the rate, first convert units properly. Since 1 kilogram equals 1,000,000 micrograms, 1.6 kilograms is 1,600,000 micrograms. One week has 604,800 seconds. Therefore, dividing 1,600,000 micrograms by 604,800 seconds gives the rate. Simplifying, this results in 2.65 µg/s. I hope this answers your question.
8 0
1 month ago
A factory robot drops a 10 kg computer onto a conveyor belt running at 3.1 m/s. The materials are such that μs = 0.50 and μk = 0
inna [2210]

Response:

x = 1.63 m

Details:

mass (m) = 10 kg

μk = 0.3

velocity (v) = 3.1 m/s

Assuming that the weight of the computer is largely applied to the belt instantaneously, we can implement the constant acceleration equation below

x = v^{2}/2a

where a = μk.g, thus

x = v^{2}/2μk.g

x = (3.1 x 3.1)/(2 x 0.3 x 9.8)

x = 1.63 m

8 0
10 days ago
A long plastic rod of 20-mm diameter (k = 0.3 W/m · K and rhocp = 1040 kJ/m3 · K) is uniformly heated in an oven as preparation
inna [2210]

Response:

The temperature required to achieve this is 286.7°C.

Justification:

Provided information:

Diameter = 20 mm = 0.02 m

Le = characteristic length = 0.02/4 = 5x10⁻³m

Thermal conductivity (K) = 0.3 W/m K

Density times specific heat (ρCp) = 1040 kJ/m³ K = 1.04x10⁶

Time (t) = 3 minutes = 180 seconds

Convection heat transfer coefficient (h) = 10 W/m² K

According to transient heat analysis:

\frac{T-25}{T_{o}-25 } =e^{-(\frac{h}{L_{e}\rho Cp } )t}

\frac{200-25}{T_{o} -25} =e^{-(\frac{10}{5x10^{-3}*1.04x10^{6} })*180 } \\T_{o} =272.38C

200°C is the minimum temperature requirement; thus, we assume a value of 210°C (10°C higher) to calculate the necessary temperature:

\frac{210-25}{T_{o} -25} =e^{-(\frac{10}{5x10^{-3}*1.04x10^{6} })*180 } \\T_{o} =286.7C

6 0
17 days ago
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