A cylindrical tank of methanol has a mass of 40 kgand a volume of 51 L. Determine the methanol’s weight, density,and specific gr

Question

1 month ago

10

avity. Take the gravitational accelerationto be 9.81 m/s2. Also, estimate how much force is needed toaccelerate this tank linearly at 0.25 m/s2.

1 answer:

serg [3.5K] · Answer 1 · 2026-02-26T01:59:57+03:00

Answer:

Weight W = 392.4 N

Density $\rho$ = 784.31 $\frac{kg}{m^{3} }$

Specific gravity S = 0.78431

Force required F = 10 N

Explanation:

Given information:

Mass (m) = 40 kg

Volume (V) = 0.051 $m^{3}$

The weight W can be calculated using W = m × g

⇒ W = 40 × 9.81

⇒ W = 392.4 N

This represents the weight of the methanol.

The density $\rho$ = $\frac{mass }{volume}$

⇒ $\rho$ = $\frac{40}{0.051}$

⇒ $\rho$ = 784.31 $\frac{kg}{m^{3} }$

This indicates the methanol's density.

Specific gravity (S) = $\frac{\rho}{\rho_{water} }$

⇒ $S = \frac{784.31}{1000}$

⇒ S = 0.78431

This is the specific gravity value for methanol.

The force required to accelerate the tank can be expressed as F = ma

⇒ F = 40 × 0.25

⇒ F = 10 N

This is the amount of force needed to set the tank in motion.