Answer:
153.2 J
Explanation:
Let’s first identify our known variables:
mass (m) of the block = 10 kg
distance slid down (i.e., displacement) = 2 m
coefficient of kinetic friction (μk) = 0.2
In the following diagram, if we analyze the force component directed along the displacement, we find
Fcos 40°
100 (cos 40°)
76.60 N
The work done by the frictional force is then calculated as:
W = 
× displacement
W = 76.60 × 2
W = 153.2 J
Therefore, the work done by the frictional force equals 153.2 J
Answer:
Explanation: Kindly refer to the attached files for a detailed solution process.
Take note that the diagram file is the first one and is positioned accordingly.
That statement is incorrect!
The claim is untrue
An item of protective gear that shields individuals passing by from stray sparks or metal during the welding process performed by another worker is known as: E. Welding Screens.
An operator is a person tasked with joining two or more metals using a technique called wielding.
In the course of wielding, both sparks and tiny metallic fragments are released, which pose a danger to the operator and others working nearby.
As a result, the equipment outlined below should be worn or utilized directly by a worker actuating the wielding process:
Nonetheless, a type of protective gear that defends other workers nearby from stray sparks or metallic fragments while the operator (worker) is in the act of welding is called welding screens.
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