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irakobra
1 month ago
10

During your summer internship for an aerospace company, you are asked to design a small research rocket. The rocket is to be lau

nched from rest from the earth's surface and is to reach a maximum height of 960 m above the earth's surface. The rocket's engines give the rocket an upward acceleration so it moves with acceleration of 16.0 m/s2 during the time T that they fire. After the engines shut off, the rocket is in free fall. Ignore air resistance. What must be the value of T in order for the rocket to reach the required altitude?
Physics
1 answer:
Maru [3.3K]1 month ago
5 0
We need to break the motion down into two segments, one when the rocket's engines are active and the other when they are inactive. We must determine the height the rocket attains with the engines on and the distance it travels after engine shutdown. For this, we apply kinematic equations: In the first part, we measure the final velocity. When the engines cut off, the initial speed from the first segment becomes relevant, and the final speed will be zero due to gravitational deceleration. We can determine the total height by adding these two heights together.
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A spin bike has a flywheel in two parts—a 12.5 kg disk with radius 0.23 m, and a 7.0 kg ring with mass concentrated at the outer
Keith_Richards [3271]

Response:

Clarification:

Provided

weight of disk m=12.5 kg

diameter of disc R=0.23 m

weight of ring m_r=7 kg

Force F=9.7 N

N=180 rpm

\omega =\frac{2\pi N}{60}

\omega =6\pi rad/s

Overall moment of inertia

=Disc's moment of inertia +Ring's Moment of Inertia

=0.5\cdot 12.5\times 0.23^2+7\times 0.23^2

=13.25\times 0.23^2=0.7009 kg-m^2

At this point, Torque is T=F\times R=I\cdot \alpha

9.7\times 0.23=0.7\times \alpha

\alpha =3.18 rad/s^2

Utilizing \omega _f=\omega +\alpha t

\omega _f=0 in this scenario

0=6\pi -3.18\times t

t=\frac{6\pi }{3.18}

t=5.92 s

7 0
1 month ago
A cylinder has 500 cm3 of water. After a mass of 100 grams of sand is poured into the cylinder and all air bubbles are removed b
Keith_Richards [3271]

Answer: SG = 2.67

The specific gravity for the sand is 2.67

Explanation:

Specific gravity is determined by the formula: density of the substance/density of water

Provided information;

Mass of sand m = 100g

The volume of sand equals the volume of water it displaces

Vs = 537.5cm^3 - 500 cm^3

Vs = 37.5cm^3

Calculating density of sand = m/Vs = 100g/37.5 cm^3

Ds = 2.67g/cm^3

Density of water Dw = 1.00 g/cm^3

Thus, the specific gravity of the sand can be expressed as

SG = Ds/Dw

SG = (2.67g/cm^3)/(1.00g/cm^3)

SG = 2.67

The specific gravity of the sand stands at 2.67

3 0
1 month ago
In broad daylight, the size of your pupil is typically 3 mm. In dark situations, it expands to about 7 mm. How much more light c
Sav [3153]

Answer:

31.4 mm²

Explanation:

The ability of a telescope or eye to gather light can be expressed by the formula,

GDP=\pi } \frac{d^{2} }{4}

where d signifies the diameter of the pupil.

In bright daylight, the usual size of the pupil is 3 mm.

GDP_{b} =\pi \frac{3^{2} }{4}

Conversely, in darkness, the diameter typically enlarges to 7 mm.

GDP_{b} =\pi \frac{7^{2} }{4}

This indicates an increase in light-gathering capacity.

Increase=\pi \frac{49}{4} -\pi \frac{9}{4} \\Increase=31.4 mm^{2}

Thus, the amount of light the eye can capture is 31.4 mm².

3 0
2 months ago
1200 N-m of torque is used to drive a gear (A) of diameter 25 cm, which in turn drives another gear (B) of diameter 52 cm. What
Ostrovityanka [3204]

Response:

2.5kN.m

Details:

Torque relates directly to the pitch diameter

= Ta/Tb= Da/Db

For 120/Tb= 0.25/0.5

This gives Tb= 2.469kN.m, roughly 2.5kN.m


8 0
1 month ago
Read 2 more answers
Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air
Keith_Richards [3271]

The frequency of a sound remains constant as it departs from the source. It does not alter.

The voices of swimmers do not modify in frequency when transitioning to or from the water. Only their speed and wavelength vary.

5 0
1 month ago
Read 2 more answers
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