Response:
Clarification:
Provided
weight of disk 
diameter of disc 
weight of ring 
Force 



Overall moment of inertia
=Disc's moment of inertia +Ring's Moment of Inertia


At this point, Torque is 


Utilizing 
in this scenario


Answer: SG = 2.67
The specific gravity for the sand is 2.67
Explanation:
Specific gravity is determined by the formula: density of the substance/density of water
Provided information;
Mass of sand m = 100g
The volume of sand equals the volume of water it displaces
Vs = 537.5cm^3 - 500 cm^3
Vs = 37.5cm^3
Calculating density of sand = m/Vs = 100g/37.5 cm^3
Ds = 2.67g/cm^3
Density of water Dw = 1.00 g/cm^3
Thus, the specific gravity of the sand can be expressed as
SG = Ds/Dw
SG = (2.67g/cm^3)/(1.00g/cm^3)
SG = 2.67
The specific gravity of the sand stands at 2.67
Answer:
31.4 mm²
Explanation:
The ability of a telescope or eye to gather light can be expressed by the formula,

where d signifies the diameter of the pupil.
In bright daylight, the usual size of the pupil is 3 mm.

Conversely, in darkness, the diameter typically enlarges to 7 mm.

This indicates an increase in light-gathering capacity.

Thus, the amount of light the eye can capture is 31.4 mm².
Response:
2.5kN.m
Details:
Torque relates directly to the pitch diameter
= Ta/Tb= Da/Db
For 120/Tb= 0.25/0.5
This gives Tb= 2.469kN.m, roughly 2.5kN.m
The frequency of a sound remains constant as it departs from the source. It does not alter.
The voices of swimmers do not modify in frequency when transitioning to or from the water. Only their speed and wavelength vary.