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coldgirl
14 days ago
8

A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho

rizontal distance 3d . Which expression represents the change in the kinetic energy of the object?
Physics
1 answer:
Softa [2K]14 days ago
5 0

The alteration in kinetic energy is \Delta K = 3Fd

Clarification:

According to the work-energy principle, the task performed on an object corresponds to the alteration in its kinetic energy. In mathematical terms:

W=K_f -K_i= \Delta K

where:

W signifies the work performed on the object

K_f denotes the kinetic energy at the end

K_i indicates the kinetic energy at the start

Furthermore, when the force is exerted in line with the object’s motion, the work done is expressed as:

W=F\Delta x

Here,

F represents the force’s magnitude

\Delta x denotes the object’s displacement

In this scenario, the force impacting the object is

F

While the distance moved is the horizontal length traveled, hence

\Delta x = 3d

Consequently, the work accomplished is

W=(F)(3d)=3Fd

Thus, the alteration in kinetic energy amounts to

\Delta K = 3Fd

Learn more about work and kinetic energy:

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Answer:

a)n= 3.125 x 10^{19 electrones.

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Explanation:

La corriente 'I' = 5A =>5C/s

diámetro 'd'= 2.05 x 10^{-3 m

radio 'r' = d/2 => 1.025 x 10^{-3 m

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a) La cantidad de electrones que pasan por la bombilla cada segundo se determina mediante:

I= Q/t

Q= I x t => 5 x 1

Q= 5C

Como sabemos que: Q= ne

donde e es la carga del electrón, es decir, 1.6 x 10^{-19C

n= Q/e => 5/ 1.6 x 10^{-19

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b) La densidad de corriente 'J' en el cable se calcula como

J= I/A => I/πr²

J= 5 / (3.14 x (1.025x 10^{-3)²)

J= 1.515 x 10^{6 A/m²

c) La velocidad típica 'V_{d' de un electrón se expresa como:

V_{d = \frac{J}{n|q|}

    =1.515 x 10^{6 / 8.5 x 10^{28} x |-1.6 x 10^{-19|

V_{d =1.114 x 10^{4m/s

d) De acuerdo con estas ecuaciones,

J= I/A

V_{d = \frac{J}{n|q|} =\frac{I}{nA|q|}

Si utilizaras un cable de doble diámetro, ¿cuáles de las respuestas anteriores cambiarían? ¿Aumentarían o disminuirían?

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1) Density of gasoline = 0.748 g/cm^3

Gasoline's density is less than that of corn syrup, indicating it will float in corn syrup.

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Water's density is also less than that of corn syrup, meaning it will float in corn syrup.

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Honey's density exceeds that of corn syrup, so it will sink in corn syrup.

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