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steposvetlana
18 days ago
6

In broad daylight, the size of your pupil is typically 3 mm. In dark situations, it expands to about 7 mm. How much more light c

an it gather?
Physics
1 answer:
Sav [2.2K]18 days ago
3 0

Answer:

31.4 mm²

Explanation:

The ability of a telescope or eye to gather light can be expressed by the formula,

GDP=\pi } \frac{d^{2} }{4}

where d signifies the diameter of the pupil.

In bright daylight, the usual size of the pupil is 3 mm.

GDP_{b} =\pi \frac{3^{2} }{4}

Conversely, in darkness, the diameter typically enlarges to 7 mm.

GDP_{b} =\pi \frac{7^{2} }{4}

This indicates an increase in light-gathering capacity.

Increase=\pi \frac{49}{4} -\pi \frac{9}{4} \\Increase=31.4 mm^{2}

Thus, the amount of light the eye can capture is 31.4 mm².

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If a 50.0-kg mass weighs 554 n on the planet saturn, calculate saturn’s radius
ValentinkaMS [2425]

Answer:

17.35 × 10^(-6) m

Explanation:

Mass; m = 50 kg

Weight; W = 554 N

From the formula:

W = mg

This simplifies to; 554 = 50g

g = 554/50

g = 11.08 m/s²

Also, using the formula;

mg = GMm/r²

hence; g = GM/r²

Rearranging gives;

r = √(GM/g)

With G as a known constant of 6.67 × 10^(-11) Nm²/kg²

r = √(6.67 × 10^(-11) × 50/11.08)

r = 17.35 × 10^(-6) m

8 0
22 days ago
A 25kg child sits on one end of a 2m see saw. How far from the pivot point should a rock of 50kg be placed on the other side of
Sav [2230]

Answer:

A rock weighing 50kg should be positioned at a distance of 0.5m from the pivot of the seesaw.

Explanation:

τchild=τrock  

We will utilize the formula for torque:

(F)child(d)child)=(F)rock(d)rock)

The gravitational force acts equally on both objects.

(m)childg(d)child)=(m)rockg(d)rock)

We can eliminate gravity from both sides of the equation for simplification.

 (m)child(d)child)=(m)rock(d)rock)  

Now employing the given masses for the rock and child. The seesaw's total length is 2 meters, with the child sitting at one end, placing them 1 meter from the center of the seesaw.

(25kg)(1m)=(50kg)drock

Solve for the distance where the rock should be positioned in relation to the seesaw's center.

drock=25kg⋅m50kg

drock=0.5m

6 0
26 days ago
1) Compute the travel time ratio of the other objects to the hollow cylinder. 2) Discuss how the travel time ratio of solid cyli
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Answer:

(1) Utilize the information provided in Table R2 and the error propagation principle to calculate the travel time ratio (with errors) of the other objects compared to the hollow cylinder? ℎ?. Complete Table R5 below. [6] Table R5 Solid cylinder Billiard ball Racquetball?? ℎ? ± ± ± (2) Examine how the solid cylinder's ratio to the hollow cylinder supports or contradicts the theoretical ratio in Eq. (8) stated in the manual. Compute the percentage error and discuss. [4] Answer: (3) Based on the travel time ratio, determine (i) if the billiard ball is solid or hollow, and (ii) if the racquetball is solid or hollow. Provide your reasoning. (Answers may vary if your measurements lack sufficient clarity.) [4]

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Image of page 4

PHYS2125 Physics Laboratory I ©2018 Kuei Sun The University of Texas at Dallas 5 Answer: (4) Identify the object in Table R2 with the highest SEOM. Provide reasoning for the relatively high SEOM and suggest improvements. [3] (5) Discuss TWO potential systematic errors in measurement. [3] Answer: **Please attach your calculation details. Use as many pages as needed; calculations that reflect your understanding may earn partial credit. **Ensure your workspace and equipment are identical to how you left them.

Explanation:

6 0
10 days ago
1. A U.S. manufacturer wants to sell computer equipment to companies in Honduras. Because the U.S. government limits trade with
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If the U.S. government prohibits the manufacturer from exporting their products to Honduras, the manufacturer will forfeit the non-refundable application fee of $2,700. Additionally, due to the restrictions on trade with Honduras, the manufacturer must secure an export license from the Department of Commerce, potentially leading to reduced demand for U.S. goods. Furthermore, the total value of product exports must reach at least $10,800 while the license is active to justify the application and licensing fees.
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10 days ago
According to the first rule, if a force pulls on one end of a rope, the tension in the rope equals the magnitude of the pulling
Sav [2230]

Answer:

The provided documents adequately explain the situation. We'll identify the force exerted on the rope using Newton's third law, which underscores that this problem relates to the concept of equilibrium.

The outcome reveals that "The tension T1 in rope 1 matches the force F.

Explanation:

According to Newton's third law, for every action, there is an equal and opposite reaction.

Refer to the documents for a thorough solution and clarification of the issue.

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