In broad daylight, the size of your pupil is typically 3 mm. In dark situations, it expands to about 7 mm. How much more light c
1 answer:
Answer:
31.4 mm²
Explanation:
The ability of a telescope or eye to gather light can be expressed by the formula,
where d signifies the diameter of the pupil.
In bright daylight, the usual size of the pupil is 3 mm.
Conversely, in darkness, the diameter typically enlarges to 7 mm.
This indicates an increase in light-gathering capacity.
Thus, the amount of light the eye can capture is 31.4 mm².
You might be interested in
Answer:
W = -510.98 J
Explanation:
Force = 43 N, 61° SW
Displacement = 12 m, 22° NE
The work done is calculated using:
W = F*d*cos(A)
where A is the angle between the applied force and displacement.
The angle A between the force and displacement is determined as A = 61 + 90 + 22 = 172°
Hence, W = 43 * 12 * cos(172)
This results in W = -510.98 J
The negative result indicates that the work is done contrary to the direction of the force applied.
Response:
A=0.199
Clarification:
We know that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=To determine the amplitude of oscillations.
Energy for oscillator=
Where =Angular frequency
A=Amplitude
Using the formula
Therefore, the amplitude of oscillation=A=0.199
answer:
Objects in vertical motion are an illustration of non-uniform motion. At the peak of the circle, centripetal force is balanced by the object's weight. Therefore, the minimum speed required at this top point is given by v = 
= 
= 5.23 m/s. As the sphere descends from the top to the bottom of the circle, according to the law of conservation of energy, potential energy can be expressed as 
where u is the velocity at the lowest point. Consequently, the modified equation is
=
=
= 11.71 m/s. The collision of the dart with the bullet is an inelastic one. According to the conservation of momentum: v =
=
=
= 58.55 m/s. Thus, the dart's minimum initial speed for the combined system to complete a circular loop post-collision is 58.55 m/s.