Answer: 339.148N
Explanation:
Given data:
Time (t) = 47s
Initial speed (U) = 0m/s
Final speed (V) = 9.5m/s
Mass of B = 540kg
Frictional force on B = 230N
Since both boats are linked, movement of A causes B to move as well.
What is the acceleration of boat A?
Applying the motion formula:
V = u + at
9.5 = 0 + a * 47
a = 9.5 / 47
a = 0.2021 m/s²
To determine the force necessary to accelerate boat B, as both boats experience the same force:
F = Mass * acceleration
F = 540 * 0.2021 = 109.14N
Given that there is a frictional force of 230N acting on boat B, the overall force (Tension) becomes:
Tension = frictional force + applied force = (109.14 + 230)N = 339.148N
To determine the average net force, we can calculate acceleration using:
x = 0.5*a*t^2
v = a*t
where x=3.6m and v=185 m/s.
Thus,
t=v/a and therefore x = 0.5*a*(v/a)^2 = 0.5 * (v^2)/a
which gives us a= (0.5*v^2)/x
Since we have the known values of v and x, we can compute a by substituting these numbers.
The average net force is then given as:
F = m*a,
with m=7.5kg.
Answer:
The pressure measured at this moment is 0.875 mPa
Explanation:
Given that,
Flow energy = 124 L/min
Boundary to system P= 108.5 kJ/min
We are tasked with finding the pressure here
Applying the pressure formula
Here, 
Where, v refers to velocity
Insert the values into the equation
Therefore, the pressure at this moment is 0.875 mPa
Response:
210.3 degrees
Justification:
The total force acting on charge A is 59.5 N
Apply the x and y components of the net force to determine the direction
atan (y/x)
Answer:
The outcome of adding 999mm to 100m is 101m.
Explanation:
That's my belief.
