The question appears to be incomplete. Here’s the complete inquiry:
Samir is quite skilled with the gun. When he targets a specific aim at the shooting range, he has a 0.95 probability of striking it. On one occasion, Samir sets out to shoot 10 targets consecutively.
If he has the same chance of hitting each of the 10 targets, what is the likelihood that he will miss at least one?
Response:
40.13%
Step-by-step breakdown:
Let 'A' represent the event of successfully hitting all targets in 10 trials.
The complement of 'A' is 
Now, since Samir has a consistent probability of hitting each target at 0.95.
Now, 
We know that the combined probability of an event and its complement equals 1.
<pThus,

Consequently, the probability that he misses at least one target among 10 attempts is 40.13%.
Answer:
(value - mean)/standard deviation.
Now substitute 78 for the value, 84.5 for the mean, and 3.1 for the standard deviation.
Step-by-step explanation:
Answer:
The resulting value is 2.381
Step-by-step explanation:
Using the information presented in the question, we will calculate the evidence supporting the professor's hypothesis
Given that:
x₁ = 74,
n₁ = 36
s₁ = 8
x₂ = 68
n₂ = 36
s₂ = 10
The hypotheses can be outlined as:
The critical value is t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀₁
thus,
t₃₆+₃₆-₂,₀.₀₁ = t₇₀,₀.₀ = 2.381
This implies a range of -2.381 to 2.381
Thus, we can support the professor's assertion.