The patient needs to receive 285.71 ml.
1000 ml contains 70 gr of glucose.
x contains 20 gr of glucose.
x=1000*20/70
Answer:
The salt identified is barium chloride.
Explanation:

The moles of barium sulfate produced are 
per the reaction, 1 mole of barium sulfate arises from 1 mole of
.
Therefore, 0.0480 moles result from:
of
.
The quantity of
used amounts to 10.00 g
Moles of
= \frac{10.00 g}{\text{Molar mass}}[/tex]

The molar mass of
is 208.33 g/mol
The closest answer to our calculation is
.
The correct identification is barium chloride, which has a molar mass of 208.2 g/mol.
Answer:
2.5 g of platinum
Explanation:
A catalyst is a substance added to a reaction to enhance the reaction speed. It does not undergo any change during the reaction, meaning it remains unchanged after the reaction concludes. The role of a catalyst is to provide an alternative pathway for the reaction by reducing the activation energy required. Therefore, a catalyzed reaction occurs more rapidly and requires less energy compared to an uncatalyzed one.
Since catalysts do not get involved in reactions and retain their mass post-reaction, the amount of platinum will stay the same (2.5g). The mass can only alter if a substance participates in the chemical process. Thus, this is the response.
The density of human fat is
. The mass of the pure fat is 11.1 lbs.
First, convert the mass from pounds to grams as follows:
1 lb=453.592 g
Thus,

Density is defined as mass per unit volume, meaning volume can be calculated as:

By substituting the values,

Consequently, the volume gained by the individual will be
.
Answer :
The percentage ionic character (%IC) equals 10%, indicating the bond is mostly covalent with slight polarity.
Percent Ionic Character:
This reflects the fraction of ionic nature within a polar covalent bond. The formula for %IC (% ionic character) is:

Here, Xa is the electronegativity of atom A and Xb is that of atom B.
Given: The compound is TiAl₃.
Electronegativity of Ti = 2.0
Electronegativity of Al = 1.6 (as shown in the provided image)
Substitute these values into the formula:



The value of e⁻¹ equals 0.90.
Therefore, percent ionic character = (1 - 0.90) × 100
Percent Ionic Character = 10%
Because the % IC is only 10%, which is relatively low, the bond is classified as covalent with minimal polarity.