Response: The moles in 369 grams of calcium hydroxide are 4.98 moles
Reasoning: Given,
Mass of calcium hydroxide = 369 g
Molar mass of calcium hydroxide = 74.093 g/mole
Formula used:
Now substituting the provided values into this formula, you will find the moles of calcium hydroxide.
Thus, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles
Moving on to the second issue
Let's tackle the second question first. Once you grasp that, the first question will be simpler. By the way, this is an excellent question to clarify. The concepts of less than and more than can be quite tricky in the sciences. Every question you encounter that utilizes less or more should be approached with caution.
As altitude increases, air pressure decreases (essential term: less highlight this sentence in color. Take a moment to reflect on it.)
As the pressure declines, less energy (again, key term) is required for water molecules to escape the surface. Thus, the boiling temperature is lower than it would be at sea level.
Answer to problem two: Lower
Problem One
Water reaches its boiling point when the greatest number of molecules can leave the water's surface. Equal to is the right answer. Although pinpointing the exact answer can be challenging, equal to is indeed the correct response.
At standard temperature and pressure, it is established that 1 mole of gas has a volume of 22.4 liters.
According to the periodic table:
the molar mass of oxygen is 16 g
and the molar mass of hydrogen is 1 g
Hence, the molar mass of water vapor is calculated as 2(1) + 16 = 18 g
Thus, 18 g of water occupies 22.4 liters, therefore:
the volume for 32.7 g is (32.7 x 22.4) / 18 = 40.6933 liters
At 30°C, glucose has a solubility of 1.25 g per gram of water. Given that the density of water at this temperature is 1 g/mL, the mass corresponding to 400 mL of water is also 400 g. Therefore, the concentration of the solution is calculated as 550 g divided by 400 g of water, which gives 1.375 g of glucose per gram of water. Since this concentration exceeds the solubility limit for glucose at this temperature, the solution can be classified as SATURATED.
