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OlgaM077
3 days ago
9

Determine the relative formula mass of hexasodium difluoride using the periodic table below. A. 138 g/mol B. 176 g/mol C. 20 g/m

ol D. 42 g/mol
Chemistry
2 answers:
VMariaS [1K]3 days ago
4 0

Answer:

B. 176 g/mol

Explanation:

chemistry ed tell

lions [985]3 days ago
3 0

Answer:

Option B. 176 g/mol

Explanation:

Let's begin by establishing the chemical formula for hexasodium difluoride:

Hexasodium indicates there are 6 sodium atoms.

Difluoride signifies there are 2 fluorine atoms.

Consequently, the formula for hexasodium difluoride is Na6F2.

The relative formula mass of a compound is determined by adding the atomic weights of its elements together.

Thus, the relative formula mass for hexasodium difluoride, Na6F2, is calculated as follows:

Molar mass of Na = 23 g/mol

Molar mass of F = 19 g/mol

Relative formula mass Na6F2 = (23x6) + (19x2)

= 138 + 38

= 176 g/mol

Thus, the relative formula mass of hexasodium difluoride, Na6F2, equals 176 g/mol

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Which of the following reactions is a redox reaction? (a) K2CrO4 + BaCl2 → BaCrO4 + 2KCl (b) Pb2+ + 2Br- → PbBr2 (c) Cu + S → Cu
castortr0y [923]

(c) Cu + S → CuS is classified as a redox reaction

Explanation:

The following reactions are presented:

(a) K₂CrO₄ + BaCl₂ → BaCrO₄ + 2 KCl

(b) Pb²⁺ + 2 Br⁻ → PbBr₂

(c) Cu + S → CuS

Reaction (c) represents a redox reaction, as the oxidation states of the elements are changing. In this case:

Cu + S → CuS

In its elemental form, Cu has an oxidation state of 0, while in CuS (copper sulfide), its oxidation state changes to +2.

Similarly, S in its elemental form has an oxidation state of 0 and is -2 in CuS (copper sulfide).

Learn more about:

redox reactions

7 0
1 day ago
Valproic acid, used to treat seizures and bipolar disorder, is composed of C, H, and O. A 0.165-g sample is combusted to produce
VMariaS [1037]

Answer:

The empirical formula is = C_4H_8O

The Valproic acid formula is = C_8H_{16}O_2

Explanation:

Mass of the produced water = 0.166 g

Molar mass of water = 18 g/mol

The moles of H_2O are calculated as 0.166 g /18 g/mol = 0.00922 moles.

In 1 mole of water, there are 2 moles of hydrogen atoms.

Thus,

Moles of H = 2 x 0.00922 = 0.01844 moles

Each hydrogen atom's molar mass is 1.008 g/mol.

Hydrogen mass in the molecule = 0.01844 x 1.008 = 0.018588 g

Mass of produced carbon dioxide = 0.403 g

Molar mass of carbon dioxide = 44.01 g/mol

The moles of CO_2 are calculated as 0.403 g  /44.01 g/mol = 0.009157 moles.

Each carbon atom's presence is 1 mole in 1 mole of carbon dioxide.

So,

Moles of C = 0.009157 moles

The molar mass of carbon is 12.0107 g/mol.

Carbon mass in molecule = 0.009157 x 12.0107 = 0.11 g

Since Valproic acid comprises only hydrogen, oxygen, and carbon, the oxygen mass in the sample = Total mass - Carbon mass  - Hydrogen mass.

The sample's overall mass = 0.165 g.

Oxygen mass in the sample = 0.165 - 0.11 - 0.018588 = 0.036412 g  

The molar mass of oxygen is 15.999 g/mol.

Moles of O  = 0.036412  / 15.999  = 0.002276 moles

Taking the simplest ratio for H, O, and C yields:

0.01844: 0.002276: 0.009157

= 8: 1: 4

The empirical formula becomes C_4H_8O

While molecular formulas detail the precise count of atoms for each element, empirical formulas represent the simplest form or reduced ratio of these elements in the compound.

Consequently,  

The molecular mass equals n × Empirical mass.

Here, n is a positive integer from 1, 2, 3...

Empirical mass = 4×12 + 8×1 + 16 = 72 g/mol.

Molar mass = 144 g/mol.

Thus,  

The molecular mass = n × Empirical mass.

144 = n × 72

⇒ n = 2

The Valproic acid formula is = C_8H_{16}O_2

7 0
7 days ago
A certain liquid has a density of 2.67 g/ cm3. what is the mass of 30.5 ml of this liquid? (
lorasvet [956]
Hello!

density = 2.67 g/cm³

volume = 30.5 mL

Thus:

Mass = density * volume

Mass = 2.67 * 30.5

Mass = 81.435 g 
4 0
6 days ago
A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6
alisha [964]
Specific heat refers to the quantity of heat a material can absorb or release to alter its temperature by one degree Celsius. To calculate specific heat, we apply the equation for the heat absorbed by the system. The heat taken in or released by a system can be expressed by multiplying the mass of the substance by its specific heat capacity and the change in temperature. The formula is:
Heat = mC(T2-T1)
By substituting the provided values, we can find C, the specific heat of the substance.
2510 J = 0.158 kg (1000 g / 1 kg)(C)(61.0 - 32.0 °C) C = 0.5478 J/g°C
8 0
5 days ago
Read 2 more answers
A chamber with a fixed volume is shown above. The temperature of the gas inside the chamber before heating is 25.2 C and it’s pr
KiRa [971]

Answer:

Explanation:

Given data:

Initial temperature T₁ = 25.2°C = 298.2K

Initial pressure P₁ = 0.6atm

Final temperature = 72.4°C = 345.4K

What we need to find:

Final pressure = ?

To determine this, we apply a modified version of the combined gas law with constant volume. This simplifies our calculations to:

\frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }

Here, P and T signify pressure and temperatures, 1 refers to initial and 2 to final temperatures.

Now we can substitute the known variables:

\frac{0.6}{298.2}   = \frac{P_{2} }{345.4}

P₂ = 0.7atm

3 0
14 days ago
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