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1 month ago

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Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat

ed from one electrode to the other, gains kinetic energy Ek. The distance between the electrodes is now changed to d. What is the gain in kinetic energy of an electron that is accelerated from one electrode to the other?

1 answer:

Yuliya22 [3.3K]1 month ago

7 0

Answer:

Explanation:

The distance between the electrodes is denoted as d.

The kinetic energy of the electron is represented as Ek when the electrodes are positioned at a distance of "d" apart.

Our goal is to determine the kinetic energy when they are separated by a distance of d/3.

K.E = ½mv²

It’s important to note that the mass remains constant; only velocity varies.

Additionally,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Assuming constant acceleration

Hence, m and a are fixed,

therefore,

K.E is directly related to d

Thus, as d increases, K.E increases, and conversely, when d decreases, K.E decreases.

Consequently,

K.E_1 / d_1 = K.E_2 / d_2

With K.E_1 equating to E_k

and d_1 being d

while d_2 is represented as d/3

This leads to K.E_2 = K.E_1 / d_1 × d_2

Thus, K.E_2 = E_k × ⅓d / d

Finally,

K.E_2 = ⅓E_k

Therefore, the resultant kinetic energy is one third of the original E_k

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2 months ago

A particle with mass 1.81×10−3 kg and a charge of 1.22×10−8 C has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^. What are

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Answer:

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The spring constant needs to be computed.

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If the block is swapped out for one with double the original mass,

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2 months ago

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