"a certain sprinkler releases water at the rate of 150 liters per hour. if the sprinkler operated for 80 minutes, how many liter

Answer: 339.148N

Explanation:

Given data:

Time (t) = 47s

Initial speed (U) = 0m/s

Final speed (V) = 9.5m/s

Mass of B = 540kg

Frictional force on B = 230N

Since both boats are linked, movement of A causes B to move as well.

What is the acceleration of boat A?

Applying the motion formula:

V = u + at

9.5 = 0 + a * 47

a = 9.5 / 47

a = 0.2021 m/s²

To determine the force necessary to accelerate boat B, as both boats experience the same force:

F = Mass * acceleration

F = 540 * 0.2021 = 109.14N

Given that there is a frictional force of 230N acting on boat B, the overall force (Tension) becomes:

Tension = frictional force + applied force = (109.14 + 230)N = 339.148N

The most effective question for the student to determine whether the substance is metal or nonmetal would be option C.

Explanation:

Here’s a revised version of the requirements;

Fill in the blanks with the appropriate terms. Picture a force gauge fixed between the rope and the saddle of the chain carousel. If you keep your feet off the ground while the vehicle is not in motion, the dynamometer shows A / B. When the carousel is spinning, you’ll see C / D displayed on the dynamometer.

A. Your weight including the saddle

C. Value of the rope's strength

B. Your weight

D. Value of the centripetal force

Answer:

D, C, B, A

Explanation:

The derivative from a velocity-time graph provides the acceleration value.

Segment A

Segment B

Segment C

Segment D

Sorted from the lowest to the highest acceleration:

D, C, B, A

1) The electric potential energy can be defined as the product of the electric potential and the associated charge:

where
q refers to the charge
V denotes the electric potential

In this scenario, the charge on the rod is , and the potential energy is , thus we may rearrange the earlier formula to find the electric potential at the tip:


2) Using this same formula, if the charge changes to , the resulting electric potential will be: