Answer: 6.25 m/s^2
Explanation:
The distance from Vinny to the ramp is 200m.
He has a maximum of 8 seconds to cover that distance.
The starting velocity is 0m/s.
The initial position is 0m.
To find the acceleration needed, we assume constant acceleration A.
a(t) = A.
To calculate the velocity, we integrate over time, noting that the constant of integration is zero since initial velocity is 0.
v(t) = A*t
For calculating position, we integrate again over time.
p(t) = 0.5*A*t^2
To cover 200m in 8 seconds:
p(8s) = 200m
0.5*A*(8s)^2 = 200m
A*32s^2 = 200m
A = 200m/32s^2 = 6.25 m/s^2
This represents the minimum acceleration required, while a greater acceleration would allow him to reach the 200m in a shorter time frame.