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Veronika
20 days ago
9

Vinny is on a motorcycle at rest, 200 m away from a ramp that jumps over a gully. Calculate the minimum constant acceleration Vi

nny must have to get to the ramp in 8 s before his pursuers catch up with him.
Physics
1 answer:
kicyunya [2.2K]20 days ago
7 0

Answer: 6.25 m/s^2

Explanation:

The distance from Vinny to the ramp is 200m.

He has a maximum of 8 seconds to cover that distance.

The starting velocity is 0m/s.

The initial position is 0m.

To find the acceleration needed, we assume constant acceleration A.

a(t) = A.

To calculate the velocity, we integrate over time, noting that the constant of integration is zero since initial velocity is 0.

v(t) = A*t

For calculating position, we integrate again over time.

p(t) = 0.5*A*t^2

To cover 200m in 8 seconds:

p(8s) = 200m

0.5*A*(8s)^2 = 200m

A*32s^2 = 200m

A = 200m/32s^2 = 6.25 m/s^2

This represents the minimum acceleration required, while a greater acceleration would allow him to reach the 200m in a shorter time frame.

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Answer

Given:

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Velocity, v = 0.38 m/s

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