The paraboloid intersects the x-y plane when x²+y²=9, defining a circle with a radius of 3, centered at the origin.
<span>Utilizing cylindrical coordinates (r,θ,z), the paraboloid transforms into z = 9−r² and f = 5r²z. </span>
<span>If F represents the average of f over the area R then F ∫ (R)dV = ∫ (R)fdV </span>
<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>
<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>
<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>
<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>
<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>
<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>
<span>Thus, F = 10935π/8 ÷ 81π/2 = 135/4</span>
Answer:
Step-by-step explanation:
Hello!
To determine whether boys excel in math classes compared to girls, two random samples were collected:
Sample 1
X₁: score achieved by a boy in calculus
n₁= 15
X[bar]₁= 82.3%
S₁= 5.6%
Sample 2
X₂: score obtained by a girl in calculus
n₂= 12
X[bar]₂= 81.2%
S₂= 6.7%
To estimate a confidence interval for the difference between the average percentages of boys and girls in calculus, it's essential that both variables come from normally distributed populations.
For utilizing a pooled variance t-test, it is also required that the population variances, though unknown, are assumed to be equal.
The confidence interval can then be calculated with:
[(X[bar]_1 - X[bar]₂) ± 
* 
]
[(82.3 - 81.2) ± 1.708 * (6.11 * 
]
[-2.94; 5.14]
Using a 90% confidence level, the interval [-2.94; 5.14] is expected to encompass the true difference between the average percentages achieved by boys and girls in calculus.
I hope this is of assistance!
The reason is rooted in the angle addition postulate. If we have the scenario where TR is a line intersecting segment VS at point R, we can establish that by applying the angle addition postulate, we can deduce that x is equal to 30. In option (1), which uses the substitution property of equality, this condition cannot be utilized correctly here. Option (3) involving the subtraction property of equality does not apply either. Lastly, option (4) regarding the addition property of equality is also inappropriate for deriving the value of x.
The volume of a cylinder can be determined using the formula pi*h*d^2/4, which leads us to V = pi*(39 mm)(39 mm)^2 / 4 = 46,589 mm^3. Dividing the mass of 1 kg by the volume of 46,589 mm^3 results in a density of 2.1464 x 10^-5 kg/mm^3. Typically, density is expressed in kg/m^3, so we convert this by multiplying by 1x10^9, yielding a density of 21,464 kg/m^3.
