Let's start by calculating the cost of the first 10 boxes, which totals $75, and the next 10 boxes cost $55.
Together, these 20 boxes amount to $130 spent. With $18 remaining, you can purchase 4 more boxes since 18 divided by 4.5 equals 4.
Therefore, the maximum number of boxes you can buy with $148 is 24.
Jerome's share of the total profit amounts to one-third. To determine the overall profit of the company, multiply his profit by 3.
If he earned $150,000, the calculation would be:
150,000 × 3 = $450,000
So, the total profit is $450,000.
The dot simply represents multiplication.
The question is missing some information. It should be phrased as follows:
<span><span>A container has 50 electronic components, with 10 identified as defective. If 6 components are randomly selected from the container, what is the probability that at least 4 of them are not defective? Additionally, if 8 components are drawn at random from the container, what is the probability that exactly 3 are defective?
</span>Answers
<span>Part 1. 0.02
Part 2. </span></span>0.0375<span><span>
</span>Explanation
Probability denotes the likelihood of an event occurring. It is computed as:
probability = (Number of favorable outcomes)/(Number of total outcomes)
Part 1
When 6 components are chosen, if 4 are confirmed functioning, then 2 must be defective.
P(at least 4 functional) = 4/40</span>× 2/10
= 1/10 × 1/5
= 1/50
= 0.02
Part 2
Choosing 8 components, if 3 are defective, then 5 are functioning.
P(3 defective) = 3/40 × 5/10
= 15/400
= 3/80
= 0.0375
Initially, we must determine the median from the provided dataset. To achieve this, we need to sort the values:
12, 15, 18, 20, 23, 23, 28
Thus, the median appears to be 20
To ensure the median remains unchanged, the eighth hour would need to have 20 visitors, allowing the revised dataset to be:
12, 15, 18, 20, 20, 23, 23, 28
I hope this clarifies things!
Answer:
ACE = ECD is the solution
Step-by-step explanation:
