Answer:
0.40
Step-by-step explanation:
The percentage of members who engage only in long-distance running is 8%
Therefore, the probability that a member focuses solely on long-distance running is P(A) = 0.08
The percentage of members who participate exclusively in field events is 32%
Thus, the probability of a member competing only in field events is P(B) = 0.32
The percentage of members acting as sprinters is 12%
So, the probability that a member is a sprinter is P(C) = 0.12
We need to determine the probability that a team member is either an exclusive long-distance runner or an only field event competitor, which equates to finding P(A or B). Since these two events cannot occur simultaneously, we can express this as:
P(A or B) = P(A) + P(B)
Substituting the known values results in:
P(A or B) = 0.08 + 0.32 = 0.40
Thus, the likelihood that a randomly selected team member runs exclusively long-distance or participates solely in field events stands at 0.40
Try this method:
When a graph shifts right, replace 'x' with 'x' minus the number.
When it shifts down, subtract the number from 'y'.
So the final equation becomes: y = 4(x - 5)² - 18.
The answer is A.
To determine the result of multiplying 0.003 by 10, you will simply multiply as such. A straightforward method is to shift the decimal point one place to the right (it would shift two places for multiplying by 100, and three for 1000, etc.). The same rule applies when dividing; just ensure to move left instead.
Hence, the result is 0.03.
<span>I hope that was helpful!!!</span>
2ab x cos(C) = 7 since
a^2 + b^2 - 2ab x cos(C) = c^2
2ab x cos(C) = a^2 + b^2 - c^2
2ab x cos(C) = 2^2 + 2^2 - 1^2
2ab x cos(C) = 7
I believe it's around $62, though I'm uncertain. Sorry for the lack of precision, but wish you all the best in life! <3
