The final mass will be slightly lower due to evaporation. I learned this back in third grade, so it's surprising you're in high school and don't know this.
(6-16)/4.0=-2.5 m/s²
The car's acceleration is -2.5 m/s²
<span>A centripetal force maintains an object's circular motion. When the ball is at the highest point, we can assume that the ball's speed v is such that the weight of the ball matches the required centripetal force to keep it moving in a circle. Hence, the string will not become slack.
centripetal force = weight of the ball
m v^2 / r = m g
v^2 / r = g
v^2 = g r
v = sqrt { g r }
v = sqrt { (9.80~m/s^2) (0.7 m) }
v = 2.62 m/s
Thus, the minimum speed for the ball at the top position is 2.62 m/s.</span>
Answer:
The properties of ligand-gated ion channels include:
a. They play a crucial role in the nervous system by altering sodium and calcium levels within cells.
b. Their significance is primarily linked to the nervous system.
c. They are vital for the nervous system, responsible for modulating sodium and calcium levels in cells, and they respond to chemical signals by either opening or closing.
Explanation:
Ligand-gated ion channels (LICs or LGICs), often called ionotropic receptors, represent a class of trans-membrane ion-channel proteins that open to permit the flow of ions like Na+, K+, Ca2+, and/or Cl− across membranes in reaction to the binding of chemical signals. Their function contrasts with that of voltage-gated ion channels, which are triggered by changes in voltage across membranes (i.e., when depolarization occurs) and are responsive to membrane potentials. In comparison to GPCRs that utilize secondary messengers, ligand-gated channels operate upon the binding of a ligand (a specific chemical signal). Both types of channels are essential for the effective activation of the post-synaptic neuron.
1) Vf = Vo - gt; Setting Vf = 0 gives Vo = gt, resulting in Vo = 9.8 m/s^2 * 1.5 s = 14.7 m/s. 2) The displacement is calculated as d = Vo*t - gt^2 / 2 = 14.7 m/s * 1.5 - 9.8 m/s^2 * (1.5 s)^2 / 2 = 11.02 m.
