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masya89
5 days ago
15

What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?

Mathematics
2 answers:
Leona [12.1K]5 days ago
6 0
2(3x - 1) ≥ 4x - 6 | Initial equation
6x - 2 ≥ 4x - 6 | Distributing 2 across the parentheses
2x - 2 ≥ -6 | Removing 4x from both sides
2x ≥ -4 | Adding -2 to both sides of the equation
x ≥ -2 | Dividing each side by 2

Thus, x must be at least -2 for inclusion in the solution set.
AnnZ [11.9K]5 days ago
3 0

Answer:

Solution Value: -2

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25 days ago
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Given:

The inequality is

-10+8x

To find:

The step that is missing in the resolution of the given inequality.

Solution:

Step 1: The equation provided.

-10+8x

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-10+8x-8x

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Step 3: Add 4 to both sides.

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8 0
1 month ago
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Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Details: The cardiac output is assessed using the dye dilution technique with 3 mg of dye.

Goal: To determine the cardiac output value.

Solution:

Cardiac output formula:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Utilize integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Insert the value into 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Consequently, Cardiac output:F=0.055 L\s

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Response:

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