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DochEvi
12 days ago
9

Which statements are true about the graph of y ≤ 3x + 1 and y ≥ –x + 2? Check all that apply. 1.The slope of one boundary line i

s 2.
2.Both boundary lines are solid.
3.A solution to the system is (1, 3).
4.Both inequalities are shaded below the boundary lines.
5.The boundary lines intersect.

Mathematics
2 answers:
Leona [4.2K]12 days ago
7 0

Answer:

2.Both boundary lines are solid.

3.A solution to the system is (1, 3).

5.The boundary lines intersect.

Step-by-step explanation:

We have

y\leq 3x+1 ----> inequality A

The solution area for inequality A is the region shaded beneath the solid line y=3x+1.

The slope of that solid line is 3.

The coordinates (1,3) fit within the solution set of inequality A.

y\geq -x+2 ----> inequality B

The solution area for inequality B is the shaded part above the solid line y=-x+2.

The slope of this solid line is -1.

The coordinates (1,3) also lie within the solution set of inequality B.

The overall solution for the inequalities is the region shaded between the two solid lines.

Please refer to the attached figure.

Verify each statement

1.The slope of one boundary line is 2.

This statement is False.

2.Both boundary lines are solid.

This statement is True.

3.A solution to the system is (1, 3).

This statement is True.

4.Both inequalities shade below their respective boundary lines.

This statement is False.

5.The boundary lines do intersect.

This statement is True.

The point of intersection is (0.25,1.75).

Refer to the attached figure.

zzz [4K]12 days ago
4 0

Answer:

2.Both boundary lines are solid.

3.A point that satisfies the system is (1, 3).

5.The boundary lines cross each other.

Step-by-step explanation:

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