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Taya2010
1 month ago
11

An ether solution of PhCO2H (A), PhNH2 (B), and PhCH3 (C) is extracted with aqueous NaOH. The ether layer will contain what comp

ound(s) after the extraction?
Chemistry
1 answer:
Anarel [2.9K]1 month ago
8 0
The ether layer will consist of aniline and toluene following the extraction process. Explanation: Solvent extraction separates compounds based on their solubilities in two distinct immiscible liquids; typically, one being water and the other, an organic solvent like ether in this instance. PhCO₂H (benzoic acid) interacts with NaOH, resulting in a highly soluble benzoate ion in water yet poorly soluble in ether, thus it remains in the aqueous layer. Conversely, PhNH₂ (aniline) dissolves well in organic solvents such as ether while having minimal or no solubility in water; PhCH₃ (toluene) possesses solubility in ether whilst being insoluble in water. Hence, post-extraction, the ether layer encompasses aniline and toluene.
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If two solutions with concentrations of 0.4 M sugar and 0.7 M sugar respectively are separated by a semipermeable membrane, duri
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Response: Water molecules migrate from the dilute to the concentrated solution

Clarification:

During osmosis, when a solution is separated by a semipermeable membrane, the solvent (commonly water) moves from the less concentrated solution, regarding solute content, through the semipermeable membrane towards the solution with a higher concentration to balance the concentration levels between the two solutions.

Thus, in this scenario, water molecules flow from the 0.4M sugar solution to the 0.7M sugar solution through the semipermeable membrane.

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2 months ago
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I think the right choice is C. Coal, as it's utilized in making a multitude of products across the globe. I trust this information is useful to you.:)
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2 months ago
Read 2 more answers
Determine the percent yield for the reaction
Alekssandra [3086]

Answer:

The percent yield of Br₂ in this reaction amounts to 96.15%

Explanation:

The reaction's balanced stoichiometric equation is:

2 NaBr + 1 Cl₂ → 2 NaCl + 1 Br₂

To calculate the percent yield:

Percent yield = 100% × (Actual yield)/(Theoretical yield)

To determine the theoretical yield:

5.29 g of NaBr reacts with an excess of chlorine; therefore, NaBr is the limiting reagent, controlling the possible yield of products.

We convert 5.29 g of NaBr to moles.

Number of moles = (Mass)/(Molar mass)

Molar Mass of NaBr = 102.894 g/mol

Number of moles = (5.29/102.894) = 0.0514121329 = 0.05141 mole

According to the stoichiometry of the reaction:

2 moles of NaBr yield 1 mole of Br₂

Thus, 0.05141 mole of NaBr will produce (0.05141×1/2) mole of Br₂, which is 0.0257 mole of Br₂

Theoretical yield = Expected mass of Br₂ from the reaction

= (Number of moles) × (Molar mass)

Molar mass of Br₂ = 159.808 g/mol

Theoretical yield of Br₂ = 0.0257 × 159.808 = 4.108 g

Calculating the percent yield:

Percent yield = 100% × (Actual yield)/(Theoretical yield)

Actual yield = 3.95 g

Theoretical yield = 4.108 g

Percent yield = 100% × (3.95/4.108) = 96.15%

Hope this is helpful!!!

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2 months ago
A 3.81-gram sample of NaHCO3 was completely decomposed in an experiment. 2NaHCO3 → Na2CO3 + H2CO3 In this experiment, carbon dio
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Answer:

The yield percentage of H_2CO_3 is 24.44%

Explanation:

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3 months ago
Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding?
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Result:

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Clarification:

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