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3 days ago

Question 1: Which of the following statement is false about conjugated systems?

Chemistry

1 answer:

Tems11 [846]3 days ago

8 0

Answer:

A conjugated system can solely consist of two alkenes: Incorrect

B. A cumulated diene is not as stable as an isolated diene.

Incorrect

Explanation:

A. A conjugated system has greater stability compared to an unconjugated system.: Correct

Owing to resonance, a conjugated system exhibits increased stability.

B. The s-trans form is preferred over the s-cis form.: Correct

Because of repulsion in the s-cis form, they are less stable.

C. A conjugated system has multiple resonance forms.Correct

This contributes to their stability.

D. A conjugated system can only comprise two alkenes: Incorrect

A conjugated system may consist of alternating double and triple bonds.

2) A trans alkene liberates less heat during hydrogenation compared to a cis alkene.

Correct

Trans alkenes are more stable than their cis counterparts, resulting in a lower heat of hydrogenation for trans alkenes.

B. A cumulated diene is less stable than an isolated diene.

Incorrect

C. Numerous products can potentially form when a conjugated diene reacts with HBr. Correct

This can result in either 1,2 or 1,4 addition.

D. Conjugated systems occur only between sp2-hybridized atoms.

Correct

Conjugation enables resonance, which is feasible in sp2 systems.

E. Conjugated double bonds rely on unhybridized p-orbitals that align with one another.

Correct

The double bond forms as a pi bond due to the lateral overlap of unhybridized p orbitals.

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How many molecules are in 13.5g of sulfur dioxide, so2?

alisha [964]

Answer: The number of sulfur dioxide molecules present is 1.27·10²³.
Calculating: m(SO₂) equals 13.5 g.
Using the formula n(SO₂) = m(SO₂) ÷ M(SO₂).
This gives n(SO₂) = 13.5 g ÷ 64 g/mol.
Resulting in n(SO₂) = 0.21 mol.
Subsequently, N(SO₂) = n(SO₂) ·Na.
Therefore, N(SO₂) = 0.21 mol · 6.022·10²³ 1/mol.
Ultimately, N(SO₂) equals 1.27·10²³.
Where n represents amount of substance.
M refers to molar mass.
Na is Avogadro's number.

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3 days ago

At -70 ∘c and 5.2 atm, carbon dioxide is in which phase?

castortr0y [923]

The conversion of -70 degrees Celsius results in 9/5 x C + 32 = 158 degrees Fahrenheit. CO2 transitions to solid state at -108.5 degrees Fahrenheit, indicating that at -70 degrees Celsius, it will be in the state commonly known as 'dry ice'.

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5 days ago

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The concentration of Si in an Fe-Si alloy is 0.25 wt%. What is the concentration in kilograms of Si per cubic meter of alloy?

KiRa [971]

Answer: The mass of Si in kilograms is, $19.55kg/m^3$

Explanation:

Given that the Si concentration in an Fe-Si alloy is 0.25 weight percent, this translates to:

Mass of Si = 0.25 g = 0.00025 kg

Mass of Fe = 100 - 0.25 = 99.75 g = 0.09975 kg

Density of Si = $2.32g/cm^3=2.32\times 10^6g/m^3$

Density of Fe = $7.87g/cm^3=7.87\times 10^6g/m^3$

Next, we need to find the quantity of Si in kilograms per cubic meter of alloy.

Si concentration in kilograms = $\frac{\text{Weight of Si in 100 g of alloy}}{\text{Volume of 100 g of alloy}}$

Si concentration in kilograms = $\frac{\text{Weight of Si in 100 g of alloy}}{\frac{\text{Wight of Fe}}{\text{Density of Fe}}+\frac{\text{Wight of Si}}{\text{Density of Si}}}$

By substituting all the provided values into this formula, we arrive at:

Si concentration in kilograms = $\frac{0.00025kg}{\frac{99.75g}{7.87\times 10^6g/m^3}+\frac{0.25g}{2.23\times 10^6g/m^3}}$

Si concentration in kilograms = $19.55kg/m^3$

Hence, the mass of Si in kilograms is, $19.55kg/m^3$

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8 days ago

Sodium only has one naturally occuring isotope, 23 Na , with a relative atomic mass of 22.9898 u . A synthetic, radioactive isot

KiRa [971]

Answer:

The mass of 22-Na included in the sample amounts to 0.0599 g

Explanation:

The total mass of the isotope mixture is 1.8385g.

It has an apparent mass of 22.9573 u.

For 23-Na, the relative atomic mass is 22.9898 u, while for 22-Na it is 21.9944 u.

Let the relative abundance of 23-Na be denoted as X.

This means that the relative abundance of 22-Na can be expressed as (1-X).

The equation formed is 21.9944 (1-X) + 22.9898 X = 22.9573.

Rearranging gives: 21.9944 - 21.9944X + 22.9898X = 22.9573.

Which simplifies to 22.9898X - 21.9944X = 22.9573 - 21.9944.

Hence, 0.9954X = 0.9639, leading to X = 0.9674.

The relative abundance of 23-Na is now identified as 0.9674.

Consequently, the relative abundance of 22-Na is 1 - 0.9674 = 0.0326.

Now, the mass of 22-Na contained within the 1.8385g sample is determined by

Relative abundance of 22-Na multiplied by the mass of the total sample = 0.0326 × 1.8385g = 0.0599 g.

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9 days ago

In how many grams of water should 25.31 g of potassium nitrate (kno3) be dissolved to prepare a 0.1982 m solution?

lions [985]

Solution:

Molality measures the concentration of a solute in a solution, defined by the amount of solute per specific mass of solvent.

Thus,

Molality = moles of solute / kg of solvent.

Therefore, kg of solvent = moles of solute / molality.

moles of solute = mass / molar mass

= 25.31 g / 101.1 g/mole

= 0.2503 mole.

kg of solvent = 0.2503 mole / 0.1982 m

= 1.263 kg

= 1263 g.

This is the final answer.

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5 days ago

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