Answer:
20 cm
Explanation:
The electric potential energy U is calculated with the formula U = kq₁q₂/r, where q₁ = 5 nC (5 × 10⁻⁹ C) and q₂ = -2 nC (-2 × 10⁻⁹ C) and r is determined as √(x - 2)² + (0 - 0)² + (0 - 0)² = x - 2. This leads to U = -0.5 µJ (-0.5 × 10⁻⁶ J), where k = 9 × 10⁹ Nm²/C².
Thus, solving for r gives us r = kq₁q₂/U
which leads to x - 2 = kq₁q₂/U
Then, rearranging gives x = 0.02 + kq₁q₂/U m
So, x = 0.02 + 9 × 10⁹ Nm²/C² × 5 × 10⁻⁹ C × -2 × 10⁻⁹ C/-0.5 × 10⁻⁶ J
Resulting in x = 0.02 - 90 × 10⁻⁹ Nm²/-0.5 × 10⁻⁶ J
This simplifies to x = 0.02 + 0.18 = 0.2 m, or 20 cm
Answer:
Explanation:
Provided:
mass of the steel ball 
initial velocity of the ball 
Final velocity of the ball 
(moving upwards)
The impulse given is determined by the change in the momentum of the object.
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Thus, the magnitude of the Impulse is 4 N-s.
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Answer:
Responses to the 3.17 punchline varied among many individuals, with some suggesting that it was a "full" moon day which prevented the astronauts from landing.
Others claimed that the astronauts took off during daylight hours when the moon was not visible. There were also comments that indicated that 'astro' refers to stars rather than satellites, explaining why they did not land.
A few even noted that 'astro naut' sounds like 'naught,' meaning zero (0), as a possible reason for their failure to land.
Response:
The intensity of light 18 feet underwater is about 0.02%
Clarification:
Employing Lambert's law
Let dI / dt = kI, where k is a proportionality factor, I represents the intensity of incident light, and t indicates the thickness of the medium
Then dI / I = kdt
Taking logarithms,
ln(I) = kt + ln C
I = Ce^kt
At t=0, I=I(0) implies C=I(0)
I = I(0)e^kt
At t=3 & I=0.25I(0), we find 0.25=e^3k
Solving for k gives k = ln(0.25)/3
k = -1.386/3
k = -0.4621
I = I(0)e^(-0.4621t)
I(18) = I(0)e^(-0.4621*18)
I(18) = 0.00024413I(0)
The intensity of light 18 feet underwater is about 0.2%
