A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir

Question

12 days ago

15

A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir

ection at 15.0 cm/s. after the collision, the 10.0 g marble moves to the right at 22.1 cm/s. find the velocity of the 25.0 g marble after the collision.

Physics

1 answer:

Yuliya22 [2.4K] · Answer 1 · 2026-03-14T01:52:53+03:00

In collisions considered elastic, the overall kinetic energy of the system remains constant, so that

KE1 = KE2

The kinetic energy before the impact can be computed as shown below.

KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
KE1 = 6125 g cm²/s²

This quantity must equal KE2, which can be derived from the post-collision conditions.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x calculated from the equation is 17.16 cm/s.

Thus, the velocity is 17.16 cm/s.