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rodikova
1 month ago
11

A mover hoists a 50 kg box from the ground to a height of 2 m. What was the change in the box's energy

Physics
1 answer:
kicyunya [3.2K]1 month ago
3 0

Response:

980 J

Clarification:

The energy change of the box is equivalent to its change in gravitational potential energy:

\Delta U = m g \Delta h

where

m = 50 kg signifies the mass of the box

g = 9.8 m/s^2 represents the acceleration caused by gravity

\Delta h= 2mindicates the height change of the box

By substituting the values, we discover

\Delta U = (50 kg)(9.8 m/s^2)(2 m)=980 J

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Answer:

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Explanation:

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P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}

P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3}..................2

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\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}

T_1 {f} = 1.48 T_2 {f}

thus, the left side temperature equals 1.48 times the right side temperature

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