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PSYCHO15rus
1 month ago
5

Calculate the molality of a 20.0% by mass ammonium sulfate (nh4)2so4 solution. the density of the solution is 1.117 g/ml.

Chemistry
1 answer:
lorasvet [2.7K]1 month ago
7 0
Hello! We have the following information: m1 (mass of solute) = 20 % m/m; M1 (molar mass of solute) (NH4)2SO4 =?; m2 (mass of solvent) =? (in Kg). To begin, we determine the solute mass (m1), knowing that: 20% m/m = 20g/100mL implies 20 → 100 mL (0.1 L) implies y g → 1 L. By calculating, y = 20/0.1 gives y = 200 g; thus, m1 = 200 g. Next, let's ascertain the Molar Mass of (NH4)2SO4: N = 2*14 = 28, H = (2*4)*1 = 8, S = 1*32 = 32, O = 4*16 = 64, totaling M1 = 132 g/mol. Now, we must find the mass (m2) of the solvent. The volume of the solvent will be: 1000 - 179 gives V = 821 mL (volume of disolvent). Assuming 1 mL = 1g, then the solvent mass is m2 = 821 g → m2 = 0.821 Kg. Now, we can apply the gathered information to the molality formula.
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The adjustable legs along with the sand table.

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