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Nadusha1986
3 months ago
12

Which substance can be decomposed by chemical means?

Chemistry
2 answers:
castortr0y [3K]3 months ago
8 0

The substance that is capable of being decomposed via chemical processes is \boxed{{\text{c}}{\text{. methane}}}.

Further Explanation:

A substance is defined as a pure form of matter, whereas a mixture refers to a combination of atoms and molecules.

Substances can be classified into two categories:

1. Element

Elements are the purest substances and represent the most basic form which cannot be decomposed by chemical means. Examples include copper, iron, and cobalt.

2. Compound

Compounds consist of two or more different elements that are bonded together through chemical bonds. These can be broken down to reveal their constituent components, which exhibit distinct properties from those of the elements that make them up. NaCl, {\text{C}}{{\text{O}}_{\text{2}}} and {{\text{H}}_{\text{2}}}{\text{O}} are examples of compounds.

a. Cobalt is classified as an element, the simplest form in which it can exist. Hence, it cannot be decomposed through chemical processes.

b. Krypton is also an element, existing in its simplest form, and therefore cannot be chemically broken down.

c. Methane consists of one carbon atom and four hydrogen atoms, making it a compound. Since compounds can be broken down chemically, methane is also able to undergo decomposition.

d. Zirconium is an element, existing in its most basic form, and is not amenable to decomposition through chemical methods.

Learn more:

1. Which sample is a pure substance?

2. Which is a characteristic of a mixture?

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Elements, compounds, and mixtures

Keywords: substance, methane, cobalt, zirconium, krypton, element, compound, chemical means, decomposed, broken down, simplest form.

castortr0y [3K]3 months ago
5 0
<span>Methane, option c, is a compound and therefore can undergo decomposition through chemical methods. It consists of one carbon atom and four hydrogen atoms. Unlike compounds, elements cannot be separated chemically. Cobalt, krypton, and zirconium are examples of elements that cannot be broken down.</span>
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Solving applied density problems Mr. Auric Goldfinger, criminal mastermind, intends to smuggle several tons of gold across Inter
KiRa [2933]

Answer:

thickness is 0.29 cm

Explanation:

To create a fake iron ball out of gold, we must ensure that its mass matches that of the iron ball. Therefore, we first find the volume of the iron ball using the provided diameter, applying the formula of 4/3 pi r^3.

Given the diameter d = 6 cm; thus, the radius r = 3 cm (d/2).

We calculate the volume of the iron ball: 4/3 * 3.14 * 3^3 = 113.04 cm^3.

The corresponding mass of the iron ball is the volume multiplied by its density: 113.04 * 5.15 g/cm^3 = 582.156 g.

This value represents the mass for the gold ball; now we determine the volume of the gold ball using its density.

Volume of gold ball = mass of gold ball/density of gold = 582.156 g/19.3 g/cm^3 = 30.1635 cm^3.

So this volume must correspond to a hollow sphere with an outer radius R = 3 cm and an unknown inner radius r.

Volume of the hollow ball can be represented as: 4/3 pi [R^3 - r^3].

Thus, 30.1635 cm^3 = 4/3 pi [3^3 - r^3].

30.1635 * 3/(4 * 3.14) = 27 - r^3.

Simplifying gives 7.2046 = 27 - r^3, resulting in r^3 = 19.7954.

Therefore, r = 2.7051 cm.

This indicates the thickness is the outer radius minus the inner radius: 3 - 2.7051 = 0.2949 cm.

Rounding to two significant figures yields

the thickness = 0.29 cm.

8 0
3 months ago
How many grams of alcl3 are required to make a 2.25m solution in 30.0 g of water?
Alekssandra [3086]
The formula for molality is \frac{\text{weight of solute (g)}}{\text{molecular weight X Weight of solvent (Kg)}}

Given: A solution's molality equals 2.25 m
The weight of the solvent is 30 g, which is the same as 0.030 kg
Molecular weight of AlCl3 is 133.34 g/mol

Thus, we have the equation, 2.25 = \frac{\text{weight of solute (g)}}{\text{133.34 X 0.030}}
Therefore, the weight of the solute (g) becomes 9.00 g

Hence, <span>9.00 g of AlCl3 is necessary for creating a 2.25m solution in 30.0 g of water</span>
8 0
2 months ago
Acetone major species present when dissolved in water
Alekssandra [3086]

The compound is acetone ( CH₃-CO-CH₃)


Explanation:


1) Acetone is represented as CH₃-CO-CH₃.


2) This is a molecule formed by covalent bonds.


3) When it dissolves, compounds with covalent bonds remain as individual molecules, indicating that the primary species in the solution are the molecules themselves, which are surrounded (solvated) by water molecules.


In contrast, ionic compounds ionize. For example, when NaCl dissolves in water, it completely breaks down into ions, hence the predominant species are the ions Na⁺ and Cl⁻, rather than the NaCl formula.


This leads to the conclusion that: when acetone dissolves in water, the primary components are the acetone molecules (there is no need to mention that water molecules are in the solution, as that isn't the question's focus).



3 0
4 months ago
Calculate the ratio of the velocity of helium atoms to the velocity of neon atoms at the same temperature.
Tems11 [2777]

Answer:

vHe / vNe = 2.24

Explanation:

To determine the velocity of an ideal gas, one should apply the formula:

v = √3RT / √M

In this equation, R represents the gas constant (8.314 kgm²/s²molK); T refers to temperature, and M indicates the molar mass of the gas (4x10⁻³kg/mol for helium and 20.18x10⁻³ kg/mol for neon). Hence:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio simplifies to:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol

vHe / vNe = 2.24

I hope it assists you!

8 0
3 months ago
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