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egoroff_w
1 month ago
5

You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31 kilograms. How would you enter this number

into the answer box?Enter your answer in kilograms usingthree significant figures. Note that the units are provided for youto the right of the answer box.m_e = __.
Chemistry
1 answer:
alisha [2.9K]1 month ago
5 0

Answer:

The response is identical to 9.11x10-31kg, which refers to electron mass.

Explanation:

The mass of an electron written in scientific notation is 9.11x10-31, which translates to 0.000000000000000000000000000000911 in standard form. While the former is more compact and easily interpretable, the latter appears cumbersome.

When discussing three significant figures, it indicates three non-zero digits. Essentially, your answer should use three digits that are not zero, starting with the first digit as non-zero, which in this case is "nine" - "9", followed by "1" and "1" as the two additional significant figures.

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he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
eduard [2782]

1) Drift velocity: 3.32\cdot 10^{-4}m/s

2. 5.6\cdot 10^{13} electrons per individual

Explanation:

1)

In a conducting material with an electric current, the drift velocity of electrons can be calculated using this equation:

v_d=\frac{I}{neA}

where

I stands for current

n represents the density of free electrons

e=1.6\cdot 10^{-19}C indicates the charge of an electron

A signifies the wire's cross-sectional area

The wire's cross-sectional area can be determined as

A=\pi r^2

where r denotes the wire's radius. Thus, the equation transforms to

v_d=\frac{I}{ne\pi r^2}

In this scenario, we have:

I = 8.0 A as the current

8.5\cdot 10^{28} m^{-3} indicates the free electron concentration

d = 1.5 mm is the diameter, making the radius

r = 1.5/2 = 0.75 mm = 0.75\cdot 10^{-3}m

So, the resulting drift velocity is:

v_d=\frac{8.0}{(8.5\cdot 10^{28})(1.6\cdot 10^{-19})\pi(0.75\cdot 10^{-3})^2}=3.32\cdot 10^{-4}m/s

2)

The entire length of the cord is

L = 3.00 m

And the cross-sectional area is

A=\pi r^2=\pi (0.75\cdot 10^{-3})^2=1.77\cdot 10^{-6} m^2

Consequently, the volume of the cord is

V=AL (1)

The number of electrons per unit volume is n, thus the total electrons in this cord would be

N=nV=nAL=(8.5\cdot 10^{28})(1.77\cdot 10^{-6})(3.0)=4.5\cdot 10^{23}

Overall, the Earth's population rounds to 8 billion individuals, equating to

N'=8\cdot 10^9

Hence, the number of electrons distributed to each person is:

N_e = \frac{N}{N'}=\frac{4.5\cdot 10^{23}}{8\cdot 10^9}=5.6\cdot 10^{13}

7 0
1 month ago
A 126-gram sample of titanium metal is heated from 20.0°C to 45.4°C while absorbing 1.68 kJ of heat. What is the specific heat o
lorasvet [2795]
The specific heat of titanium metal is 0.524 J/g°C. Given that Q = 1.68 kJ, which equates to 1680 Joules, with a mass of 126 grams and initial and final temperatures of 20°C and 45.4°C respectively, the specific heat is computed using the formula Q = (mass)(ΔT)(Cp), where ΔT = T₂ - T₁ = 25.4°C. Plugging in the numbers leads us to Cp = 0.524 J/g°C.
3 0
24 days ago
Given the following equation and heat of reaction: 2 moles of A combine with 2 moles of B to produce 6 moles of C and 26 kJ What
KiRa [2933]

Answer: The change in enthalpy will be -13.

Explanation:-

Endothermic reactions absorb heat, while exothermic reactions release heat. In the case of an endothermic reaction, the change in enthalpy is represented as positive, whereas for an exothermic reaction, it is negative.

\Delta H  \Delta H

2A+2B\rightarrow 6C+26kJWhen one mole of A combines with one mole of B to form three moles of C

2A+2B\rightarrow 6CSo the stoichiometric ratio being halved also results in the enthalpy for the reaction being halved.\DeltaH=-26kJ

Thus, for this reaction:

 

     

A+B\rightarrow 3C+\frac{26}{2}kJ

The resulting change in enthalpy is -13.

A+B\rightarrow 3C\DeltaH=-13kJ

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You are trying to make balloon sculptures. You twist the balloons gently, but they keep popping. Besides trimming your nails, ho
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Wear gloves to avoid your nails from damaging the balloons due to their soft nature.
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