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egoroff_w
15 days ago
5

You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31 kilograms. How would you enter this number

into the answer box?Enter your answer in kilograms usingthree significant figures. Note that the units are provided for youto the right of the answer box.m_e = __.
Chemistry
1 answer:
alisha [964]15 days ago
5 0

Answer:

The response is identical to 9.11x10-31kg, which refers to electron mass.

Explanation:

The mass of an electron written in scientific notation is 9.11x10-31, which translates to 0.000000000000000000000000000000911 in standard form. While the former is more compact and easily interpretable, the latter appears cumbersome.

When discussing three significant figures, it indicates three non-zero digits. Essentially, your answer should use three digits that are not zero, starting with the first digit as non-zero, which in this case is "nine" - "9", followed by "1" and "1" as the two additional significant figures.

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Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca2+, V5+, Br-
lorasvet [956]

Answer:

CaS, CaBr₂, VBr₅, and V₂S₅.

Explanation:

  • The ionic compound must exhibit neutrality; its total charge should equal zero.
  • A binary ionic compound is formed from two distinct ions.

Ca²⁺ combines with either Br⁻ or S²⁻ to create binary ionic compounds.

  • CaS is created when Ca²⁺ pairs with S²⁻ resulting in the neutral binary ionic compound CaS.
  • CaBr₂ results from the combination of one mole of Ca²⁺ with two moles of Br⁻ to form the neutral binary ionic compound CaBr₂.

V⁵⁺ can also unite with either Br⁻ or S²⁻ to produce binary ionic compounds.

  • V₂S₅ is formed when two moles of V⁵⁺ bond with five moles of S²⁻ yielding the neutral binary ionic compound V₂S₅.
  • VBr₅ is produced by combining one mole of V⁵⁺ with five moles of Br⁻ to form the neutral binary ionic compound VBr₅.

Thus, the empirical formulas for four binary ionic compounds that may be produced are: CaS, CaBr₂, VBr₅, and V₂S₅.

5 0
12 days ago
A sample of H2SO4 contains 2.02 g of hydrogen, 32.07 g of sulfur, and 64.00 g of oxygen. How many grams of sulfur and grams of o
VMariaS [1037]
Analyzing the formula for sulfuric acid reveals the molar proportions:

H: S: O
2: 1: 4

Next, we need to convert the provided mass of hydrogen into moles, calculated by:

Moles = mass / Mr
Moles = 7.27 / 1
Moles = 7.27

Thus, the number of moles for each element are:

S = 7.27 / 2 = 3.64 moles
O = 7.27 * 2 = 14.54 moles

Subsequently, the masses for sulfur and oxygen are:
S = 32 * 3.64 = 116.48 grams
O = 16 * 14.54 = 232.64 grams 
7 0
11 days ago
Classify these compounds as acid, base, salt, or other.? 1. ch3oh 3. hno3 5. nabr
KiRa [971]
<span> </span><span>1. Other (Alcohol)
3. Acidic
5. Salt

</span>
5 0
2 days ago
Read 2 more answers
The Michaelis‑Menten equation models the hyperbolic relationship between [S] and the initial reaction rate V 0 V0 for an enzyme‑
alisha [964]

Answer:

The equation formulated by Michaelis-Menten is expressed as

v₀ = Kcat × [E₀] × [S] / (Km + [S])

in which,

Kcat denotes the experimental reaction rate constant; [S] signifies the concentration of the substrate, and

Km represents the Michaelis-Menten constant.

Explanation:

Refer to the attached image for an in-depth clarification

3 0
9 days ago
65g of nitric acid are produced in a reaction. 2.5g of platinum are added to the reaction vessel at the start of the reaction to
alisha [964]

Answer:

2.5 g of platinum

Explanation:

A catalyst is a substance added to a reaction to enhance the reaction speed. It does not undergo any change during the reaction, meaning it remains unchanged after the reaction concludes. The role of a catalyst is to provide an alternative pathway for the reaction by reducing the activation energy required. Therefore, a catalyzed reaction occurs more rapidly and requires less energy compared to an uncatalyzed one.

Since catalysts do not get involved in reactions and retain their mass post-reaction, the amount of platinum will stay the same (2.5g). The mass can only alter if a substance participates in the chemical process. Thus, this is the response.

6 0
3 days ago
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