A secondary alkyl halide would be characterized by having a carbon atom connected to two other carbon atoms, with bromine attached to that carbon.
Therefore, bromo-hexane qualifies as a 2-degree or secondary alkyl halide
I believe the answer is D, though I'm not entirely certain unfortunately.
Response:
The conclusion to your inquiry is Pressure 1 = 1.73 atm
Clarification:
Data provided
Volume 1 = 5 l
Pressure 1 =?
Volume 2 = 12 l
Pressure 2 = 0.72 atm
Procedure
To resolve this issue, Boyle's law is applied
Pressure 1 x Volume 1 = Pressure 2 x Volume 2
-Finding Pressure 1
Pressure 1 = Pressure 2 x Volume 2 / Volume 1
-Replace values
Pressure 1 = 0.72 x 12 / 5
-Calculating
Pressure 1 = 8.64/5
-Final outcome
Pressure 1 = 1.73 atm
We assume that the stated 50% is measured by volume. Molarity defines the concentration in terms of moles of solute per volume of solution.
To find the moles of NaOH, use: (0.1 moles / L)(0.4 L)
n = 0.04 moles of NaOH
Assuming we start with 1 mL of 50% NaOH solution,
(1 mL solution)(1.525 g/mL)(0.50) = 0.7625 g
Then, the number of moles calculates as follows,[
0.7625 g NaOH x (1 mol / 40 g) = 0.01906 moles of NaOH
The volume of solution required can be determined by:(0.04 moles of NaOH)(1 mL solution / 0.01906 moles of NaOH)
Thus, the needed volume comes out to be 2.09 mL
Answer: 2.09 mL
