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Phoenix
1 month ago
15

A spherical weather balloon is being inflated. The radius of the balloon is increasing at the rate of 7 cm/s. Express the surfac

e area of the balloon as a function of time t (in seconds). (Let S(0) = 0.) . S(t) = cm^2?
Mathematics
2 answers:
Svet_ta [12.7K]1 month ago
7 0
R(t) = 6t 

<span>substituting into the formula </span>

<span>V = (4/3) pi * r^3 </span>

<span>V(t) = (4/3) pi * (6t)^3 </span>
<span> </span>
<span>V(t) = (4/3) pi * 216 t^3

Now multiply 4/3 by 216. </span>

<span>V(t) = 288 * pi * t^3</span>
zzz [12.3K]1 month ago
3 0

Answer:

S(t)=196\pi t^2

Step-by-step explanation:

It is given that

The radius of the balloon is increasing at a speed of 7 cm/s.

Let time equal t seconds.

In one second, the radius becomes 7 cm.

Therefore, in t seconds, the radius is R(t) = 7t.

We need to calculate the surface area of the balloon as a function of time t.

The area of a sphere can be represented as S(R)=4\pi R^2.

Incorporate the value:

S(R(t))=S(t)=4\pi (7t)^2=196\pi t^2

Thus, S(t)=196\pi t^2

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