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Katena32
13 days ago
11

Is 0.398 a whole number, interger, rational number, irrational number, or a real number

Mathematics
2 answers:
Leona [12.6K]13 days ago
7 0
It can be identified as a rational number.
Zina [12.3K]13 days ago
3 0
It is classified as a real number.
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Suppose we want to choose 2 objects, without replacement, from the 5 objects pencil, eraser, desk, chair, and lamp. (a)How many
Inessa [12570]

Answer:

a) 20 different arrangements

b) 10 different arrangements

Step-by-step explanation:

When the order of selection is significant, we utilize permutations to determine the number of arrangements; if the order does not matter, we apply combinations.

For part a)

We must select 2 items from a collection of 5, considering that order matters. This is a permutation scenario, thus we calculate 5P2.

The general formula for permutations of n items taken r at a time is:

nPr=\frac{n!}{(n-r)!}

By inserting n=5 and r=2, we have:

5P2=\frac{5!}{(5-2)!} =20

Hence, it is possible to select 2 items from a group of 5 when the selection order is relevant.

For part b)

Since the order of selection is unimportant, we use combinations to calculate the number of ways of selecting 2 items from 5, represented as 5C2.

The general formula for combinations of n items taken r at a time is:

nCr=\frac{n!}{r!(n-r)!}

Plugging n=5 and r=2 into the formula results in:

5C2=\frac{5!}{2!(5-2)!} =10

This demonstrates that we can choose 2 items from a collection of 5 when the order of selection is not significant.

3 0
1 month ago
Read 2 more answers
Explain how solving -7y > 161 is different from solving 7y > - 161
AnnZ [12381]

Step-by-step explanation:

-7y > 161

7y < 161

Dividing by 7 gives 1

161÷7=23

y=23

7y > -161

7÷7=1

-161÷7=-23

y=-23

6 0
16 days ago
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Assume that a fair die is rolled. The sample space is , 1, 2, 3, 4, 56, and all the outcomes are equally likely. Find P8. Expres
AnnZ [12381]

Answer:

P\left(8\right)=0

Step-by-step explanation:

Assuming a fair die is rolled.

  • The sample space comprises 1, 2, 3, 4, 5, 6, with all results being equally probable.

Let X represent the collection of all outcomes. Let A represent a specific outcome.

<pThus, the probability of event A occurring is:

                                                        P\left(A\right)=\frac{|A|}{|X|}

Considering that the set of all possible outcomes for a singular die roll is:

X=\left\{1,2,3,4,5,6\right\}

Notably,

|X|=6

Here,  

|A|=0   since 8 is not included in the sample space. Therefore, rolling an 8 is impossible within the defined outcomes.

<pThis leads to the conclusion that the probability is zero.

In other terms,

                        P\left(A\right)=\frac{|A|}{|X|}

                         P\left(8\right)=\frac{0}{6}=0

<pAs a result,

                   P\left(8\right)=0

5 0
1 month ago
If p+pq is 4 times p-pq, and pq does not equal to 0, which of the following has exactly one possible value? A)p B)q C)pq D)p+pq
Inessa [12570]
D is the correct option since it represents a combination where neither p nor a equals zero.
8 0
1 month ago
How much profit was generated by the sales of gold label and black label combined?
lawyer [12517]
The profit produced by combining sales of gold label and black label equals the total of their individual profits. From the table \begin{array}{ccc}&\text{Number of bottles sold}&\text{Average profit (per bottle)}\\\text{Gold label}&1,000&\$2.75\end{array} you find the gold label's profit 1,000\cdot \$2.75=\$2,750. and similarly from another table \begin{array}{ccc}&\text{Number of bottles sold}&\text{Average profit (per bottle)}\\\text{Black label}&2,000&\$1.50\end{array} find the black label's profit 2,000\cdot \$1.50=\$3,000.. Adding these yields \$2,750+\$3,000=\$5,750.. Thus, option 5 is the correct choice.
8 0
2 months ago
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