If you are anchored in a fixed spot, and a set of six waves pass underneath you during a 60 second time interval, what is the wa

<span>A force of 110 N is applied at an angle of 30</span>°<span> to the horizontal. Because the force does not align directly either vertically or horizontally with the sled, it can be broken down into two components based on sine and cosine.

For the component parallel to the ground:
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26

For the component perpendicular to the ground:
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>

Answer:

Explanation:

In this scenario, we determine the initial velocity as follows:

The final velocity in this instance can be expressed as:

It is noted that transitioning from 7m/s to 13m/s takes 8 seconds. We can apply a specific kinematic equation to find the acceleration for the first part of the journey:

Solved for acceleration, we find:

For the subsequent route, we assume constant acceleration and that the train continues for 16 seconds, beginning with an initial velocity of 13m/s from the previous segment, allowing us to calculate the final speed via the following formula:

Substituting into the equation yields:

<span>First, apply Newton's second law of motion: F = ma. Force equals mass times acceleration. This law describes force as the product of mass multiplied by acceleration (which is different from velocity). As acceleration is the variation in velocity over time, we have force = (mass * velocity) / time, leading us to conclude that (mass * velocity) / time will equal momentum / time. Hence, we derive the equation mass * velocity = momentum. Momentum = mass * velocity. For the elephant, with a mass of 6300 kg and velocity of 0.11 m/s, Momentum = 6300 * 0.11, resulting in P = 693 kg (m/s). For the dolphin, having a mass of 50 kg and moving at 10.4 m/s, Momentum = 50 * 10.4, yielding P = 520 kg (m/s). Thus, the elephant has a greater momentum (P) due to its larger size.</span>

Answer:

a = 18.28 ft/s²

Explanation:

the values provided are:

duration of force application, t= 10 s

Work done = 10 Btu

mass of the object = 15 lb

acceleration, a =? ft/s²

1 Btu = 778.15 ft.lbf

thus, 10 Btu = 7781.5 ft.lbf

m = 0.466 slug

So,

the work is equivalent to the change in kinetic energy

 

The acceleration of the object is therefore

 

 

         a = 18.28 ft/s²

the constant acceleration of the object is calculated to be 18.28 ft/s²

Answer: small barrel gun

Explanation:

It is noted that short barrel guns have a higher muzzle velocity for bullets compared to longer barrel guns.

Acceleration is determined by the change in velocity with respect to time.

For short barrel guns, the bullet reaches its muzzle velocity more quickly, leading to greater acceleration than that of bullets from long barrel guns.