Rhonda sold five appliances this week. She sold a stove for $800.00, a refrigerator for $1,250.00, a microwave for $120.00, a di

Answer:

F(n)= 0.50+0.15

Step-by-step explanation:

The starting point is 0.50. Additionally, when adding a fine of 0.15, you would consider 0.15 as well.

To determine this answer, you need to calculate the percentage change.
This involves dividing the difference in lengths by the original length. We begin with the main bridge.

4700 - 2300 = 2400
2400 divided by 4700 equals approximately 51.1% shorter.

Answer:

Option (B)

Step-by-step explanation:

The given question is incomplete; please refer to the attached document for the full details.

In the attached graph,

The parent function is defined as an absolute value function,

f(x) = |x|

When this graph is moved four units to the left, the translation rule becomes,

f(x) → f(x + 4)

Consequently, the new function following this translation is,

g(x) = f(x + 4) = |x + 4|

Now, with the graph shifted down by two units, the translated function becomes,

h(x) = g(x) - 2

h(x) = |x + 4| - 2

When reformulated as an equation, the graph can be represented by

⇒ y = |x + 4| - 2

Thus, Option (B) is the correct answer.

The illustration is omitted. Please see the attachment below.

Answer:

The area of the shaded sector is 144π square units.

Step-by-step breakdown:

Given:

The central angle for the sector is,

The circle's radius is,

The area of a sector with radius 'R' and angle can be determined with:

Substituting gives

Thus, the area of the shaded sector calculates to 144π square units.

Answer:

Part 1) The equation is

Part 2) When x=40 m, the area of the schoolyard is A=2,800 m^2

Part 3) The valid domain consists of all real numbers exceeding zero and below 75 meters

Step-by-step explanation:

Part 1) Formulate an expression for A(x)

Let

x -----> the length of the rectangular school yard

y ---> the width of the rectangular school yard

It is known that

The perimeter for the fencing (taking the school wall as one side) is

thus

-----> this is equation A

The area of the rectangular school yard is

----> this is equation B

Substituting equation A into equation B yields

Change to function notation

Part 2) What is the area when x=40?

With x equal to 40 m

substitute the value into the expression from Part 1 to determine A

   

Part 3) What would be a suitable domain for A(x) in this scenario?

We understand that

A signifies the area of the rectangular school yard

x characterizes the length of the rectangular school yard

It follows that

This forms a vertical parabola opening downwards

The vertex indicates a maximum point

The x-coordinate of the vertex corresponds to the length that maximizes the area

The y-coordinate of the vertex denotes the maximum area

The vertex corresponds to (37.5, 2812.5)

Refer to the accompanying figure

Consequently,

The peak area achieved is 2,812.5 m^2

The x-intercepts are located at x=0 m and x=75 m

The domain for A is the range -----> (0, 75)

All real numbers greater than zero and less than 75 meters