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Gnesinka
15 days ago
10

Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to

trade. Astronaut 1 tosses the 0.130 kg apple toward astronaut 2 with a speed of vi,1 = 1.05 m/s . The 0.150 kg orange is tossed from astronaut 2 to astronaut 1 with a speed of 1.18 m/s . Unfortunately, the fruits collide, sending the orange off with a speed of 1.03 m/s in the negative y direction. What are the final speed and direction of the apple in this case?
Physics
1 answer:
Softa [3K]15 days ago
5 0

Final velocity: v= 1.23 m/s angle: θ = 75.3º

To explain:

Initially, we designate the direction in which both fruits are thrown as the x-axis, meaning all initial momenta will only have horizontal components.

In the absence of external forces influencing the collision—due to the extremely brief timeframe of the event—momentum conservation applies.

As momentum is a vector quantity, both components must be maintained, leading us to establish the following equations:

p₁ₓ = p₂ₓ ⇒ -m₁. vi₁ +m₂. vi₂ = m₁. vf₁. cos θ (1)

p₁y = p₂y ⇒ 0 =m₂. vf₂ - m₁. vf₁. sin θ (2)

Substituting in the values for m1, m₂, vi₁, vi₂, and vf₂ allows us to solve for θ, the angle between the apple and the horizontal, through the following steps:

(1) -0.13 Kg. 1.05 m/s + 0.15 Kg. 1.18 m/s = 0.13. vf. cos θ

(2) 0.15 Kg. 1.03 m/s = 0.13 vf. sin θ

Taking the ratio sin θ / cos θ = 3.82 leads to tg θ = 3.82 ⇒ θ = arc tg (3.82) = 75.3º

Substituting this θ value back into (2) gives us:

0.15 kg. 1.03 m/s = 0.13 vf. sin 75.3º = 0.13. vf. 0.967

Solving for vf yields:

vf = 0.15 kg. 1.03 m/s / (0.13. 0.967) = 1.23 m/s

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Answer:

Explanation:

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Electrons bear a negative charge, protons are positively charged, and neutrons possess no charge. An atom is electrically neutral when it has an equal number of electrons and protons, but this can change if particles are removed.

1: Ionized atom model - an ionized atom carries a net charge, which can be positive or negative.

To illustrate an ionized atom, one would need to reduce the number of either electrons or protons.

2: Radioactive atom model: A radioactive atom is characterized as unstable and retains excess energy in its nucleus, often due to added neutrons or protons.

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1 month ago
The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca
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Answer:

The resulting value is E_i = 1.5596 *10^{-18} \ J.

Explanation:

The question specifies that

The wavelength is \lambda = 48.2 nm = 48.2 *10^{- 9 }\ m.

The velocity is v = 2.371*10^6 \ m/s.

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The energy of the incoming light is typically depicted mathematically as

E = \frac{h * c}{\lambda}.

Here, c represents the speed of light with the value c = 3.0 *10^{8} \ m/s.

h stands for Planck's constant with a value of h = 6.62607015 * 10^{-34 } J\cdot s.

Thus,

E = \frac{6.62607015 * 10^{-34 }* 3.0 *10^{8}}{48.2 *10^{- 9 }}

=> E = 4.12 *10^{-18} \ J.

Typically, kinetic energy is represented as

E_k = \frac{1}{2} * m_e * v^2

=> E_k = \frac{1}{2} * 9.109*10^{-31} * (2.371*10^6 )^2.

=> E_k = 2.56 *0^{-18} \ J.

The ionization energy is generally expressed mathematically as

E_i = 4.12 *10^{-18} - 2.56 *0^{-18}

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Joan and Mike's teacher show them a picture of an atom and ask them to identify it using the periodic table. Joan says the atom
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A ball collides elastically with an immovable wall fixed to the earth’s surface. Which statement is false? 1. The ball's speed i
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Answer:

Statements 4, 6 & 7 are incorrect.

Explanation:

In any elastic collision, the overall momentum vector sum of the system remains zero.

In this scenario, an elastic collision occurs between the ball and a stationary wall. The ball's velocity will consistently revert after the impact, leading to a change in direction of momentum.

The initial momentum of the ball is represented as:

p=m.v

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m = mass of the ball

v = initial velocity of the body

post-collision for the elastic interaction:

p=m.(-v)

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