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Advocard
12 days ago
9

A current of 0.001 A can be felt by the human body. 0.005 A can produce a pain response. 0.015 A can cause a loss of muscle cont

rol. In the procedures of this lesson, over 0.030 A of current traveled in the three-battery circuit. Why was this circuit safe to handle with dry hands? Include the resistance of human skin in your answer.
Physics
1 answer:
Softa [2K]12 days ago
7 0

Response:

Overall, it's safe to manage this voltage with dry hands since the current flow through the body is below the sensitivity threshold.

Clarification:

The current in your body is defined by Ohm's law

        V = I R

where I represents current, V signifies voltage, and R is resistance

In this scenario, three batteries in series produce a total voltage of V = 4.5 V, while the typical resistance of dry skin is R = 1,000,000 Ohms and wet skin has R = 100,000 Ohms

Now, let’s calculate the current flow

        I = V / R

        I = 4.5 / 1,000,000

        I = 4.5 × 10⁻⁶ A

This is the current with dry hands, indicating it's much lower than the threshold that would trigger a painful sensation in the body.

For wet skin

         I = 4.5 / 100,000

         I = 4.5 × 10⁻⁵ A

This value is small but approaches the pain threshold, indicating slight discomfort.

In summary, it is safe to handle this voltage with dry hands since the current value through the body is less than its perceived sensitivity.

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A sculptor has asked you to help electroplate gold onto a brass statue. You know that the charge carriers in the ionic solution
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Answer:

Explanation:

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3 days ago
A spring is stretched 6 in by a mass that weighs 8 lb. The mass is attached to a dashpot mechanism that has a damping constant o
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Response:

y= 240/901 cos 2t+ 8/901 sin 2t

Clarification:

To determine mass m=weight/g

  m=8/32=0.25

To calculate the spring constant

Kx=mg    (with c=6 inches and mg=8 pounds)

K(0.5)=8               (6 inches converts to 0.5 feet)

K=16 lb/ft

The governing equation for the spring-mass system is

my''+Cy'+Ky=F  

Inserting the known values yields

0.25 y"+0.25 y'+16 y=4 cos 20 t  ----(1) (given C=0.25 lb.s/ft)

Assuming the steady state equation for y is

y=A cos 2t+ B sin 2t

To determine constants A and B, we must equate this with equation 1.

Next, we find y' and y" by differentiating with respect to t.

y'= -2A sin 2t+2B cos 2t

y"=-4A cos 2t-4B sin 2t

Now, substitute the values of y", y' and y into equation 1

0.25 (-4A cos 2t-4B sin 2t)+0.25(-2A sin 2t+2B cos 2t)+16(A cos 2t+ B sin 2t)=4 cos 20 t

By comparing coefficients on both sides

30 A+ B=8

A-30 B=0

From this, we find

A=240/901 and B=8/901

Thus, the steady state response

y= 240/901 cos 2t+ 8/901 sin 2t

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10 days ago
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