The nitrogen atom of NH2 would have The nitrogen atom of {\rm NH_2} would have blank electrons around the central nitrogen atom.

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The nitrogen atom of NH2 would have The nitrogen atom of {\rm NH_2} would have blank electrons around the central nitrogen atom.

electrons around the central nitrogen atom. The nitrogen atom of NH4 would have The nitrogen atom of {\rm NH_4} would have blank electrons around the central nitrogen atom. electrons around the central nitrogen atom. The nitrogen atom of NH3 would have The nitrogen atom of {\rm NH_3} would have blank electrons around the central nitrogen atom. electrons around the central nitrogen atom.

Chemistry

1 answer:

Alekssandra [3K] · Answer 1 · 2026-04-07T05:31:57+03:00

Answer:

(a) The nitrogen atom in contains $NH_2^-$ 8 electrons surrounding the central nitrogen atom.

(b) The nitrogen atom in has $NH_4^+$ 8 electrons around the central nitrogen atom.

(c) The nitrogen atom in has $NH_3$ 8 electrons surrounding the central nitrogen atom.

Explanation:

The Lewis dot structure illustrates the connections between atoms within a molecule, additionally showing unpaired electrons present in the molecule.In this structure, valence electrons are represented as 'dots'.

Now we will determine the number of electrons linked to the central nitrogen atom in the specified molecule.

(a) The identified molecule is,

$NH_2^-$ Recognizing that nitrogen has '5' valence electrons while hydrogen has '1', we ascertain the total valence electrons in

= 5 + 2(1) + 1 = 8

According to the Lewis dot structure, this reveals 4 bonding and 4 non-bonding electrons.

$NH_2^-$ From the Lewis structure, we conclude that the nitrogen atom in

has 8 electrons surrounding it.

(b) The identified molecule is, $NH_2^-$

Knowing that nitrogen has '5' valence electrons and hydrogen has '1' valence electron, the total number of valence electrons for $NH_4^+$ = 5 + 4(1) - 1 = 8

In the Lewis dot structure, there are 8 bonding electrons and 0 non-bonding electrons.

This leads us to conclude that the nitrogen atom in

contains 8 electrons surrounding it. $NH_4^+$

(c) The identified molecule is,

$NH_4^+$

Recognizing nitrogen’s '5' valence electrons and hydrogen’s '1' brings the total valence electrons for

= 5 + 3(1) = 8 $NH_3$ Utilizing the Lewis dot structure indicates there are 6 bonding and 2 non-bonding electrons.

According to the Lewis dot structure, we conclude that the nitrogen atom in

has 8 electrons surrounding it.

$NH_2^-$