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Gnesinka
1 month ago
10

How quickly can bacterial contamination occur?

Chemistry
2 answers:
castortr0y [3K]1 month ago
7 0

Answer:

Bacteria are tiny organisms that can divide and reproduce at an astonishing rate. Under optimal conditions, a single bacterium can multiply to two million in merely seven hours.

Explanation:

lorasvet [2.7K]1 month ago
5 0
5-10 seconds xxx:) hope this is helpful.
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A generic element, Z, has two isotopes, 45Z and 47Z, and an average atomic mass of 45.36 amu. The natural abundances of the two
lorasvet [2795]
The isotopic mass of 47Z is calculated to be 46.96 amu. Isotopes of a single element differ in neutron count, and to ascertain the relative atomic mass, we consider each isotope's mass weighted by their natural abundance. This provided a computation to derive the mass of 47Z.
5 0
22 days ago
Find the specific heat of sikver in J/g C if 38.5 cal is required to heat 25.0g of silver from 31.5 C to 58.7 C (1cal=4.184 J)
alisha [2963]

Answer:

The specific heat value for silver is 0.236 J/g-C.

Explanation:

Silver has a mass of 25 grams.

The temperature shifts from 31.5° C to 58.7° C.

The required heat is equivalent to 25 g.

To determine silver's specific heat, the following equation applies:

Q=mc\Delta T

Where c represents the specific heat of silver.

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{38.5 \times 4.184}{25(58.7-31.5)}\\\\c=0.236\ J/g-C

Thus, the specific heat of silver is 0.236 J/g-C.

7 0
1 month ago
The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab
Anarel [2989]

Answer:

Please review the following responses

Explanation:

1) A solution of 100. mL contains 19.5 g of NaCl  (3.3M)

2) 100. mL of NaCl solution at 3.00 M (3 M)

3) A solution of 150. mL holds 19.5 g of NaCl  (2.2 M)

4) The concentrations of beakers 1 and 5 are identical (1.5M)

Molar mass of NaCl = 23 + 36 = 59 g

For beaker number 3:

          59 g -------------- 1 mol

           19.5 g -------------   x

  x = 19.5 x 1/59 = 0.33 mol

Molarity (M) = 0.33 mol/0.150 l = 2.2 M

For beaker number 4:

Molarity (M) = 0.33mol/0.10 l = 3.3 M

For beaker number 5:

Molarity (M) = 0.450/0.3 = 1.5 M

4 0
1 month ago
Read 2 more answers
If 3.18 x 10^23 atoms of iron react with 67.2 L of chlorine gas at STP, what is the maximum
Tems11 [2777]

84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.

Explanation:

Balanced equation:

2 Fe + 3 Cl2 → 2 FeCl3​

DATA PROVIDED:

iron =  atoms

mass of chlorine = 67.2 liters

mass of FeCl3 =?

The number of moles of iron will be calculated as

number of moles = \frac{total number of atoms}{Avagaro's number}

number of moles = \frac{3.18 x 10^23}{6.022x 10^23}

number of moles = 0.52 mol of iron

moles of chlorine gas

number of moles = \frac{mass}{molar mass of 1 mole}

Substituting the values into the equation:

n = \frac{67200}{70.96}               (molar mass of chlorine gas = 70.96 g/mol)

   = 947.01 moles

As iron is the limiting reagent therefore

2 moles of Fe lead to 2 moles of FeCl3

0.52 moles of Fe will yield

\frac{2}{2} = \frac{x}{0.52}

0.52 moles of FeCl3 is produced.

To express this in grams:

mass = n x molar mass

         = 0.52 x 162.2                   (molar mass of FeCl3 is 162.2g/mol)  

          = 84.34 grams        

3 0
1 month ago
6.74 g of the monoprotic acid KHP (MW = 204.2 g/mol) is dissolved into water. The sample is titrated with a 0.703 M solution of
eduard [2782]

Answer:

The volume of calcium hydroxide solution utilized is 0.0235 mL.

Explanation:

2KHP+Ca(OH)_2\rightarrow 2H_2O+Ca(KP)_2

Moles of KHP = \frac{6.74 g}{204.2 g/mol}=0.0330 mol

In accordance with the reaction, 2 moles of KHP react with 1 mole of calcium hydroxide, thus 0.0330 moles of KHP will react with;

\frac{1}{2}\times 0.0330 mol=0.01650 mol of calcium hydroxide

The molarity of calcium hydroxide solution = 0.703 M

Volume of calcium hydroxide solution = V

Molarity=\frac{Moles}{Volume(L)}

0.703 M=\frac{0.01650 M}{V}

V=\frac{0.01650 M}{0.703 M}=0.0235 mL

The volume of the calcium hydroxide solution utilized is 0.0235 mL.

4 0
1 month ago
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