The isotopic mass of 47Z is calculated to be 46.96 amu. Isotopes of a single element differ in neutron count, and to ascertain the relative atomic mass, we consider each isotope's mass weighted by their natural abundance. This provided a computation to derive the mass of 47Z.
Answer:
The specific heat value for silver is 0.236 J/g-C.
Explanation:
Silver has a mass of 25 grams.
The temperature shifts from 31.5° C to 58.7° C.
The required heat is equivalent to 25 g.
To determine silver's specific heat, the following equation applies:

Where c represents the specific heat of silver.

Thus, the specific heat of silver is 0.236 J/g-C.
Answer:
Please review the following responses
Explanation:
1) A solution of 100. mL contains 19.5 g of NaCl (3.3M)
2) 100. mL of NaCl solution at 3.00 M (3 M)
3) A solution of 150. mL holds 19.5 g of NaCl (2.2 M)
4) The concentrations of beakers 1 and 5 are identical (1.5M)
Molar mass of NaCl = 23 + 36 = 59 g
For beaker number 3:
59 g -------------- 1 mol
19.5 g ------------- x
x = 19.5 x 1/59 = 0.33 mol
Molarity (M) = 0.33 mol/0.150 l = 2.2 M
For beaker number 4:
Molarity (M) = 0.33mol/0.10 l = 3.3 M
For beaker number 5:
Molarity (M) = 0.450/0.3 = 1.5 M
84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.
Explanation:
Balanced equation:
2 Fe + 3 Cl2 → 2 FeCl3
DATA PROVIDED:
iron = atoms
mass of chlorine = 67.2 liters
mass of FeCl3 =?
The number of moles of iron will be calculated as
number of moles = 
number of moles = 
number of moles = 0.52 mol of iron
moles of chlorine gas
number of moles = 
Substituting the values into the equation:
n =
(molar mass of chlorine gas = 70.96 g/mol)
= 947.01 moles
As iron is the limiting reagent therefore
2 moles of Fe lead to 2 moles of FeCl3
0.52 moles of Fe will yield
= 
0.52 moles of FeCl3 is produced.
To express this in grams:
mass = n x molar mass
= 0.52 x 162.2 (molar mass of FeCl3 is 162.2g/mol)
= 84.34 grams
Answer:
The volume of calcium hydroxide solution utilized is 0.0235 mL.
Explanation:

Moles of KHP = 
In accordance with the reaction, 2 moles of KHP react with 1 mole of calcium hydroxide, thus 0.0330 moles of KHP will react with;
of calcium hydroxide
The molarity of calcium hydroxide solution = 0.703 M
Volume of calcium hydroxide solution = V



The volume of the calcium hydroxide solution utilized is 0.0235 mL.