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marin
12 days ago
5

Two objects are maintained at constant temperatures, one hot and one cold. Two identical bars can be attached end to end, as in

part a of the drawing, or one on top of the other, as in part b. When either of these arrangements is placed between the hot and the cold objects for the same amount of time, heat Q flows from left to right. Find the ratio Qa/Qb.
Physics
1 answer:
inna [3.1K]12 days ago
7 0
The ratio Qa/Qb is determined as k/2×2k, yielding a value of 1/4. In the scenario where situation 'a' embodies series and 'b' depicts parallel arrangements, the conductance for each plate is k. Thus, net conductance for series equals k/2, while for parallel it is 2k.
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The acceleration of segment D is m/s2. Rank segments A, B , C from least accelerations to greatest acceleration. Least
Ostrovityanka [3204]

Answer:

D, C, B, A

Explanation:

The derivative from a velocity-time graph provides the acceleration value.

Segment A

\frac{dy}{dx} = \frac{15m/s}{1s} = 15m/s^2

Segment B

\frac{dy}{dx} = \frac{5m/s}{1s} = 5m/s^2

Segment C

\frac{dy}{dx} = \frac{0m/s}{2s} = 0m/s^2

Segment D

\frac{dy}{dx} = \frac{-20m/s}{1s} = -20m/s^2

Sorted from the lowest to the highest acceleration:

D, C, B, A

8 0
1 month ago
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A horse does 860 j of work in 420 seconds while pulling a wagon. what is the power output of the horse? round your answer to the
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the answer is 2w
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20 days ago
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A car drives 215 km east and then 45 km north. What is the magnitude of the car’s displacement? Round your answer to the nearest
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The Pythagorean Theorem can be utilized here: Imagine a car navigating through traffic—when it turns left to travel north, a right angle of 90 degrees is formed. However, the displacement is always the shortest distance connecting the origin and the endpoint, which forms a triangle in this scenario. In a right triangle, the Pythagorean theorem applies: 215^2+45^2=c^2; therefore, v=√(215^2+45^2).
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In the reaction at Blood Falls, iron and oxygen combine to form iron oxide, which is called rust (water is also present). The re
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1 month ago
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A crate on a motorized cart starts from rest and moves with a constant eastward acceleration ofa= 2.60 m/s^2. A worker assists t
Keith_Richards [3271]

Response:

To find power, we must first determine the work done by the force.

1) We will use the following equation to calculate work:

\int\limits {F} \, dx

The force is provided by the problem; our goal is to express 'dx' in terms of 't'

2) It's known that:

\frac{dV}{dt} = a = 2.6

Thus, we have:

v = 2.6t

Then:

\frac{dx}{dt} = V = 2.6t\\ \\dx = 2.6t*dt

3) Finally, substituting all known values gives us:

\int\limits^{4.7}_{0} {5.4t*2.6t} \, dt

After some calculations, the resulting work is:

161.9638 J.

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8 0
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