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Studentka2010
3 months ago
9

Suppose that now you want to make a scale model of the solar system using the same ball bearing to represent the sun. How far fr

om it would you place a sphere representing the earth? (Center to center distance please.) The distance from the center of the sun to the center of the earth is 1.496×10111.496×1011 m and the radius of the sun is 6.96×1086.96×108 m.
Physics
1 answer:
serg [3.5K]3 months ago
7 0

Response:

d = 0.645 m (assuming the ball bearing's radius is 3 mm)

Clarification:

Here's what we know:

  • The distance from the sun's center to earth's center is 1.496x10¹¹m = d_{e}
  • The sun's radius measures 6.96x10⁸m = r_{s}

We need to estimate a radius for the ball bearing; let's take the radius to be 3 mm = r_{b}.

First, we need to determine how much larger the sun's radius is compared to the ball bearing's radius using the equation below:

\frac{r_{s}}{r_{b}} = \frac{6.96\cdot 10^{8}m}{3\cdot 10^{-3}m} = 2.32\cdot 10^{11}

Now, let's figure out the distance from the sun's center to the center of a spherical model for the earth, d_{s}:

[tex] d_{s} = \frac{d_{e}}{r_{s}/r_{b}} = \frac{1.496 \cdot 10^{11} m}{2.32\cdot 10^{11}} = 0.645 m

I trust this is beneficial for you!

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Answer:

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Explanation:

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At point 1, the total field is calculated as -E₁ + E₂ = 0.

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