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irakobra
2 months ago
8

Suppose that an owner of the same dog breed has also taken some measurements. They notice that the surface area of the dog has i

ncreased by a factor of 3 over a period of four years. Determine the change in the dog's relative surface area in this time period.
Physics
1 answer:
inna [3.1K]2 months ago
7 0

Answer:

The surface area of the dog changes from A to 3A

Explanation:

It is stated that the dog's surface area has increased by a factor of 3 over four years.

We need to calculate the change in the relative surface area of the dog over this timeframe.

Let’s assume the initial surface area is A.

Since the surface area has been multiplied by 3,

it follows that the surface area after four years is equal to 3×A = 3A.

Thus, the dog's surface area transitions from A to 3A.

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A simple harmonic wave of wavelength 18.7 cm and amplitude 2.34 cm is propagating along a string in the negative x-direction at
Ostrovityanka [3204]

Answer

Given:

Wavelength = λ = 18.7 cm

                  = 0.187 m

Amplitude, A = 2.34 cm

Velocity, v = 0.38 m/s

A)  Calculate the angular frequency.

     f = \dfrac{v}{\lambda}

     f = \dfrac{0.38}{0.187}

     f =2.03\ Hz

Angular frequency,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) Calculate the wave number:

      K = \dfrac{2\pi}{\lambda}

     K= \dfrac{2\pi}{0.187}

    K =33.59\ m^{-1}

C)

Since the wave is traveling in the -x direction, the sign is positive between x and t

y (x, t) = A sin(k x - ω t)

y (x, t) = 2.34 sin(33.59 x - 12.75 t)

4 0
2 months ago
Assume that the cart is free to roll without friction and that the coefficient of static friction between the block and the cart
Keith_Richards [3271]

Answer:F=\frac{(M+m)g}{\mu _s}

Explanation:

Provided:

The trolley, with mass M, is allowed to roll freely without friction.

The coefficient of friction between the trolley and mass m is \mu _s.

A force F is applied to mass m.

The acceleration of the system is

a=\frac{F}{M+m}

The frictional force will counterbalance the weight of the block.

The frictional force is =\mu _sN

N=ma

\mu _sN=mg

\mu _sma=mg

\mu _s=\frac{g}{a}

F=\frac{(M+m)g}{\mu _s}

6 0
2 months ago
Read 2 more answers
A supplier wants to make a profit by buying metal by weight at one altitude and selling it at the same price per pound weight at
Ostrovityanka [3204]

The appropriate choice is C.

In physics, the law of gravity helps us understand how gravity varies with height. As altitude increases, so too does the experience of gravity. Changes in altitude also result in variations in weight, though these differences are not particularly significant. Consequently, weighing metals at different heights shows negligible variance as the impact of gravity remains constant across them.

3 0
1 month ago
Select the areas that would receive snowfall because of the lake effect.
Keith_Richards [3271]

Result:

- Grand Marais

- Two Harbors

- Duluth

Explanation:

The locations likely to receive snowfall due to lake effect include Grand Marais, Two Harbors, and Duluth. These areas are situated directly along the shores of Lake Superior, one of the world’s largest lakes. Its substantial water volume significantly influences the local climate, generating a lot of humidity in the air and considerable evaporation, both of which lead to cloud formation and, when temperatures drop adequately, result in significant snowfall rather than rain.

8 0
1 month ago
What is the internal energy (to the nearest joule) of 10 moles of Oxygen at 100 K?
serg [3582]

Response:

U = 12,205.5 J

Clarification:

To determine the internal energy of an ideal gas, use the following equation:

U=\frac{3}{2}nRT        (1)

U: internal energy

R: ideal gas constant = 8.135 J(mol.K)

n: number of moles = 10 mol

T: the temperature of the gas = 100K

Substituting the parameter values into equation (1):

U=\frac{3}{2}(10mol)(8.135\frac{J}{mol.K})(100K)=12,205.5J

The overall internal energy for 10 moles of Oxygen at 100K is 12,205.5 J

6 0
1 month ago
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