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Nina
2 months ago
14

A scuba diver has his lungs filled to half capacity (3 liters) when 10 m below the surface. If the diver holds his breath while

quietly rising to the surface, what will the volume of the lungs be (in liters) at the surface? Assume the temperature is the same at all depths. (The density of water is 1.0 x 103 kg/m3.)
Physics
1 answer:
Keith_Richards [3.2K]2 months ago
4 0
To address this problem, Boyle's Law must be applied, which states that the initial and final pressures and volumes are related as follows: Where, P₀ and V₀ represent the initial pressure and volume, while P and V refer to the final pressure and volume. The endpoint pressure in this scenario is atmospheric pressure. Thus, using the given equation, we can find the volume the lungs would occupy at the surface.
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A 3030 cmcm wrench is used to loosen a bolt with a force applied 0.30.3 mm from the bolt. It takes 6060 NN to loosen the bolt wh
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Complete Question

A 30 cm cm wrench is employed to loosen a bolt, with force applied 0.30m from the bolt. It requires 60 N to loosen the bolt when force is applied perpendicular to the wrench. How much force would be necessary if the force were applied at a 30-degree angle from perpendicular?

Response:

The strength needed is F_{\theta } = 69.28 \ N

Clarification:

According to the problem, we know that

    The length of the wrench is L = 30 cm = \frac{30}{100} = 0.3 \ m

    The distance from the bolt is  d = 0.30 m

      The force necessary to loosen the bolt is F = 60 N

       The angle of application is \theta = 30 ^o

Generally, the torque required for loosening the bolt is defined as

       \tau = F * d

        \tau = 60 * 0.3

        \tau = 18 Nm

Now for the bolt to loosen at \theta the torque at 90° must equal that at \theta

Thus, the torque at \theta is represented mathematically as

          \tau = F_{\theta }d cos \theta

substituting values gives us

           18 = F_{\theta } * 0.3 cos (30)

           F_{\theta } = \frac{18}{0.3 cos (30)}

           F_{\theta } = 69.28 \ N

       

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Response:

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Clarification:

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