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SpyIntel
6 days ago
15

Find the change in volume for a metallic dental filling due to the difference between body temperature (37.0°C) and the temperat

ure of the ice cream you ate (-6.2°C). The initial volume of the filling is 21.0 mm3, and its expansion coefficient is α = 42.0 × 10−6 K−1
Physics
1 answer:
serg [1.1K]6 days ago
5 0

Answer:

The change in the volume of a metallic dental filling caused by the temperature difference is 0.1143 mm.

Explanation:

Given:

Body temperature is, T_1=37\ \°C

Temperature of the ice cream is, T_2=-6.2\ \°C

The filling's initial volume is, V=21.0\ mm^3

The thermal expansion coefficient is, \alpha =42.0\times 10^{-6}\ K^{-1}

It is known that the coefficient of volume expansion is associated with thermal expansion as follows:

\gamma=3\alpha=3\times 42.0\times 10^{-6}=126\times 10^{-6}\ K^{-1}

Now, the change in volume for a metallic dental filling can be calculated as:

\Delta V=V\gamma(T_1-T_2)\\\Delta V=21\times 126\times 10^{-6}(37-(-6.2))\\\Delta V=2646\times(37+6.2)\times 10^{-6}\\\Delta V=2646\times 43.2\times 10^{-6}\\\Delta V=0.1143\ mm^3

Thus, the change in volume for a metallic dental filling from the temperature variance is 0.1143 mm.

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The right answer is (a).

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Answer:

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Transformation of Energy

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As the object descends the frictionless ramp, it converts all its potential energy into kinetic energy, represented as

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\boxed{\displaystyle W=-m.g.H}

The negative sign indicates that the work acted against the direction of movement, meaning the force and displacement are 180° apart.

This outcome is independent of the distance D needed to halt the block or the kinetic friction coefficient.

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The car that is the furthest from the finish line is: Car III (Choice C).

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Applying the principle of energy conservation from the Top of the hill to the Bottom of the hill

Energy at the Top of the hill equals Energy at the Bottom of the hill

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Case B:

B.60 kg 35 N/m.9 m

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Case C:

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Case D:

D.84 kg 32 N/m.95 m

m = weight of the car = 0.84 kg

k = spring's stiffness = 32 N/m

h = height of the hill = 0.95 m

x = spring's compression = 0.25 m

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(0.5) k x² + mgh = (0.5) m v²

(0.5) (32) (0.25)² + (0.84 x 9.8 x 0.95) = (0.5) (0.84) v²

v = 4.6 m/s


thus, the closest result is from case C at 5.1 m/s




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