Answer: 24.24 m
Explanation:
A player launches a football 50.0 m at an angle of 61° to the north of west. We will break this down into vertical and horizontal elements.
Horizontal component: 50 cos 61° = 24.24 m directed westward
Vertical component: 50 sin 61° = 43.73 m directed toward the north.
Refer to the diagram below.
Therefore, the westward displacement of the football corresponds to the horizontal component of the displacement, which is 24.24 m.
Answer:
W = -510.98 J
Explanation:
Force = 43 N, 61° SW
Displacement = 12 m, 22° NE
The work done is calculated using:
W = F*d*cos(A)
where A is the angle between the applied force and displacement.
The angle A between the force and displacement is determined as A = 61 + 90 + 22 = 172°
Hence, W = 43 * 12 * cos(172)
This results in W = -510.98 J
The negative result indicates that the work is done contrary to the direction of the force applied.
Answer:
Explanation:
Refer to the attached diagram for enhanced clarity regarding the question.
One of the blocks weighs 1.0 kg and accelerates downward at 3/4g.
g denotes the acceleration due to gravity.
Let M represent the block with known mass, while 'm' signifies the mass of the other block and 'a' refers to the acceleration of body M.
Given M = 1.0 kg and a = 3/4g.
By applying Newton's second law;
For the body with mass m;
T - mg = ma... (1)
For the body with mass M;
Mg - T = Ma... (2)
Combining equations 1 and 2 gives;
+Mg -mg = ma + Ma
Ma-Mg = -mg-ma
M(a-g) = -m(a+g)
Substituting M = 1.0 kg and a = 3/4g into this equation leads to;
3/4 g-g = -m(3/4 g+g)
3/4 g-g = -m(7/4 g)
-g/4 = -m(7/4 g)
1/4 = 7m/4
Multiplying gives: 28m = 4
m = 1/7 kg
Hence, the mass of the other box is 1/7 kg
