Answer:
1.5 × 10³⁶ light-years
Explanation:
A particular square area in interstellar space measures roughly 2.4 × 10⁷² (light-years)². To find the area of a square, the following formula is utilized:
A = l²
where,
A represents the area of the square
l denotes the length of one side of the square
Thus, l = √A = √2.4 × 10⁷² (light-years)² = 1.5 × 10³⁶ light-years
Answer: 592.37m
Explanation:
Person D is represented by the blue line.
The total displacement is calculated by subtracting the initial position from the final position. Starting at (0,0), the path consists of moving down two blocks, then right six blocks, followed by moving up four blocks, and finally left one block.
Here, I consider the positive direction of the x-axis to the right and the positive direction of the y-axis as upward.
Thus, the new coordinates will be, with B representing a block:
P =(6*B - 1*B, -2*B + 4*B) = (5*B, 2*B)
Given that B = 110m
P = (550m, 220m)
The displacement corresponds to the length of the vector, since the change from the initial position (0,0) to P is simply P:
P = √(550^2 + 220^2) = 592.37m
Answer:
4.05 m/s
Explanation:
We will express the varying velocities as vectors.
Newton moves northward at 3.90 m/s from Daniel's stationary position.
V_n = 3.9 j
Assuming Pauli runs relative to Daniel at velocity X.
The relative velocity of Newton as seen by Pauli will be
3.9 j - X
Given that
the relative velocity of Newton with respect to moving Pauli = 1.1 i (1.1 towards the east).
Thus,
3.9 j - X = 1.1 i
X = -1.1 i + 3.9 j.
Magnitude of X
X² = 1.1² + 3.9²
X = 4.05 m/s
Therefore, Pauli runs relative to Daniel at 4.05 m/s.
The direction will be west of north at an angle θ,
Tan θ = 1.1 / 3.9
