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AysviL
2 months ago
13

A sample of 14 joint specimens of a particular type gave a sample mean proportional limit stress of 8.48 MPa and a sample standa

rd deviation of .79 MPa ("Characterization of Bearing Strength Factors in Pegged Timber Connections, "J. of Structural Engr., 1997: 326-332). Assume the population has normal distribution. Calculate a 95% lower confidence bound for the true average proportional limit stress of all such joints. Calculate a 95% confidence interval for the true average proportional limit stress of all such joints.
Mathematics
1 answer:
Inessa [12.5K]2 months ago
6 0

Answer:lower limit -8.106

8.02≤μ≤8.93 represents the confidence interval

Step-by-step explanation:

given

mean(x)=8.48 MPa

standard deviation(s)=0.79 MPa

as the population standard deviation is unknown, we utilize the t-statistic

formula

tα,n-1=t=

}[/tex]

\frac{x-μ}{[tex]\frac{s}{√n}

where

s-sample standard deviation

x-sample mean

μ-population mean

n-sample size

for a 95% confidence interval and 13 degrees of freedom

t=1.771 (one tail, considering only the lower bound is needed)

for lower bound

x-t×

≤μ

8.48-1.771×

≤μ\frac{s}{√n}

μ≥8.106

\frac{0.79}{√14}

confidence interval

t=2.160 (two-tailed)x-t×

≤μ≤x+t×

8.48-2.160×\frac{s}{√n}≤μ≤8.48+2.160×\frac{s}{√n}

8.02≤μ≤8.93 establishes the needed confidence interval\frac{0.79}{√14}\frac{0.79}{√14}

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