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Pani-rosa
9 days ago
15

We fully submerge an irregular lump of material in a certain fluid. The fluid that would have been in the space now occupied by

the lump has a mass of . (a) When we release the lump, does it move upward, move downward, or remain in place
Physics
1 answer:
Ostrovityanka [3.2K]9 days ago
4 0

Answer:

the lump descends

Explanation:

The full articulation of the query is

Upon fully submerging a 3 kg lump of material in a certain fluid, the fluid that would have occupied the space now filled by the lump weighs 2 kg. (a) When released, does the lump float up, sink, or remain steady

(a)

F_{b} = Buoyant force acting upward on the lump

M = mass of irregular lump = 3 kg

m = mass of fluid displaced = 2 kg

The upward buoyant force on the lump is given by the weight of the displaced fluid, thus

F_{b} = mg = (2) (9.8) = 19.6 N

the weight of the irregular lump of material is represented as

W = mg\\W = (3) (9.8)\\W = 29.4 N

Given that the weight of the lump downward exceeds the upward buoyant force, the lump will indeed descend

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A wildlife researcher is tracking a flock of geese. The geese fly 4.0 km due west, then turn toward the north by 40° and fly ano
serg [3582]

Answer:

(a). The distance traveled is 7.06 km towards the west.

(b). Their displacement magnitude is 7.51 km.

Explanation:

The information given states that,

The geese initially move 4.0 km directly west, then alter course to the north at a 40° angle, covering an additional 4.0 km.

Based on the diagram,

(a). To determine the distance

We will apply the distance formula

AD=AB+BD

Insert the values into the equation

D= 4+4.0\cos40^{\circ}

D=7.06\ km

The resultant distance is 7.06 km westward.

(b). We will find the total displacement's magnitude

Using the displacement formula

AC=\sqrt{(CD)^2+(AD)^2}

Insert the values into the equation

AC=\sqrt{(4.0\sin40)^2+(7.06)^2}

AC=7.51

The total displacement magnitude is 7.51 km.

In conclusion, (a). The traveled distance is 7.06 km towards the west.

(b). The magnitude of their total displacement is 7.51 km.

7 0
1 month ago
Laser beam with wavelength 632.8 nm is aimed perpendicularly at opaque screen with two identical slits on it, positioned horizon
Softa [3030]

Response:

1 slit width = 0.158 mm, slit separation = 0.633 mm, distance between diffraction maxima = 12.7 mm

Explanation:

This involves defining several terms:

λ, the wavelength of the beam

D, the distance from the plane to the slit

x, the distance between minima in the diffraction pattern (in single slit setups)

w, the fringe width for double slit setups

1. In a double slit experiment, the fringe width is also recognized as the distance between Maxima.

Thus, w=λD/d, leading to d=λD/w when rearranged.

So, d= (632.8 x 10^-9 x 1 x 10^3)/1

which equals d= 0.633mm.

For single slit diffraction, minima are defined by a*sinΘ= m*x

where a is the slit width and m is an integer.

For small angles, it simplifies to Θ= (x/D) = (λ/a), allowing us to solve for a:

a = λD/a

a = (632.8x10^-9 x 1)/4

yielding a= 0.158mm.

2. A grating with 20 slits/mm gives d= 1/20mm= 0.05x10^-3.

To find y (the distance between maxima), apply y= λL/d:

Finally, y= (632.8 x 10^-9 x 1)/0.05x10^-3, which results in y= 12.7mm.

6 0
1 month ago
Which model is used to describe the interaction of external forces that affect an organization's strategy and ability to compete
ValentinkaMS [3465]

Answer:

Competitive forces model

Explanation:

The Competitive forces model is a crucial instrument in strategic analysis aiming to assess an organization’s competitiveness. Commonly referred to as the "Five Force Model of Porter", this framework includes five key factors: the intensity of rivalry among existing competitors, the negotiating power of buyers, the threat posed by potential new entrants, the bargaining strength of suppliers, and the risk of substitute products or services.

These elements significantly influence an organization's competitive strategy and its likelihood of success.

5 0
1 month ago
The δe of a system that releases 12.4 j of heat and does 4.2 j of work on the surroundings is __________ j.
Yuliya22 [3333]

For this issue, the answer is clarified as the system takes in energy (+). The surroundings contribute 84 KJ of work. Whenever a system is receiving work from its surroundings, the value will be positive. Therefore, it sums to 12.4 KJ + 4.2 = 16.6 KJ.

5 0
1 month ago
You stand on a bathroom scale in a moving elevator. what happens to the scale reading if the cable holding the elevator suddenly
Sav [3153]

A bathroom scale operates under gravitational influence. Typically, a reading is captured when your body applies force onto the scale. Yet in this scenario, as both you and the scale move downwards, your body ceases to press against the scale. Consequently, the result is:

<span>The scale reading will instantly drop to zero</span>

7 0
1 month ago
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